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postnew [5]
3 years ago
10

The product of six and a number is 66 find the number

Mathematics
1 answer:
Allushta [10]3 years ago
3 0

Answer:

11

Step-by-step explanation:

If you add 11 6 times, you will get 66 or if you multiply 11 times 66 you will get 66.

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a rectangle box has length 12 inches, width 15 inches, and a height of 17 inches. Find the angle between the diagonal of the box
ANTONII [103]

Answer:

0.7246 radians

Step-by-step explanation:

According to the Question,

Given that, a rectangle box has length 12 inches, width 15 inches, and a height of 17 inches

  • The length of the base diagonal (d) can be found using the Pythagorean theorem on length and width:

d = √{ (12)² +(15)² }  = √(144+225) = √369inches

  • The tangent of the angle is the ratio of the height of the box to this length

 Tan∅ = 17/√369

Taking the Tan^{-1} , we have

∅ = Tan^{-1}(17/√369) ≈ 0.7246 radians

4 0
2 years ago
Evaluate. -1/4(d+1) &lt; 2<br> Please show how
sergejj [24]

Answer:

-1/4 (d+1)< 2

(d+1) × -1 < 2×4

(d+1) × -1 < 8

-d - 1 < 8

-d < 8 + 1

-d < 9

d > -9

d = { -8, -7, -6....., 0, 1, 2, 3, 4,....}

Step-by-step explanation:

brainliest plz

4 0
2 years ago
Find GCF of -50m ^4 n ^7 and 40m ^2 n ^10
trapecia [35]
-50m^4 n^7 = 10m^2n^7(-5m^2)<span>
and
40m^2 n^10 = 10</span>m^2 n^7(4n^3)

Answer:  GCF = 10m^2 n^7
5 0
3 years ago
 what is perpendicular to y= 3x -9 and passes through the point (3,1)
GREYUIT [131]
(3,1) , \ \ y= 3x -9 \\ \\ The \ slope \ is :m _{1} =3 \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \ m _{1} \cdot m _{2} = -1 \\ \\3\cdot m_{2}=-1 \ \ /:3\\ \\ m_{2}=-\frac{1}{3}

\Now \ your \ equation \ of \ line \ passing \ through \ (3,1) would \ be: \\ \\ y=m_{2}x+b \\ \\1=-\frac{1}{ 3} \cdot3 + b

1=-1+b\\ \\ b=1+1\\ \\b=2 \\ \\ y =- \frac{1}{3}x+2


6 0
3 years ago
Martine’s town is building a volleyball court based on a scale drawing that is 40cm to 80cm and uses the scale 1cm:22.5cm write
never [62]

Answer:

y=22.5x

Step-by-step explanation:

we have that

The scale drawing is

\frac{1}{22.5}\frac{cm}{cm}

we know that

Using proportion find out the actual dimensions of the volleyball court

Let

x -----> drawing court lengths in cm

y ----> court lengths in cm

For x=40 cm

\frac{1}{22.5}\frac{cm}{cm}=\frac{40}{y}\frac{cm}{cm}\\\\y=40*22.5\\\\y=900\ cm

For x=80 cm

\frac{1}{22.5}\frac{cm}{cm}=\frac{80}{y}\frac{cm}{cm}\\\\y=80*22.5\\\\y=1,800\ cm

Find the equation for the proportional relation ship between drawing court lengths x in centimeters and court lengths in y centimeters

 A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

For x=40 cm, y=900

substitute

k=y/x -----> k=900/40=22.5

The equation is

y=22.5x

5 0
3 years ago
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