Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>
Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get
Hence amount owed at the end of 1 year is 3640
Answer:
b i think
Step-by-step explanation:
Answer:
I think you wanna know exactly it's graph
See f(x)= 2 e^x +3
e^x is exponential function which is always positive and so lies above x axis
Multiply by 2 make it's incrementation in slope and now it will pass through (0,2)
Also adding 3 shifts graph 3 unit above y axis
So Now it will pass through (0, 2+3) that is B) (0,5)
Now At x approaches to minus infinity it will shift 3 unit up from 0 to 3 So it will pass through (-infinity,3)
Now see the pic