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2 years ago

Q2. Do as directed(You can solve on a piece of paper and send picture in assignment) (4)

Mathematics

1 answer:

zepelin [54]2 years ago

8 0

Step-by-step explanation:

true equation when x is replaced by 2, and is a false ... is written in terms of P, R, and T.” In some cases, before using a formula it may be ... (2) a number line graph, or (3) interval notation.

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Express the following as: ax+by+c=0 -2x+3y=6

Cerrena [4.2K]

The expression -22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

<h3>Linear Equations</h3>

The given equation is:

-2x + 3y = 6

Comparing the equation above with ax + by + c = 0

Rewrite -2x + 3y = 6 in the form ax + by + c = 0

-2x + 3y - 6 = 0

If -2x + 3y - 6 = 0 is compared with ax + by + c = 0

a = -2, b = 3, c = -6

Therefore, the expression-22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

Learn more on linear equations here: brainly.com/question/14323743

8 0

2 years ago

Read 2 more answers

What are the focus and directrix of the parabola that is the graph of the function f(x)=x²?

Hitman42 [59]

Answer:

Step-by-step explanation:

Given

$y=x^2$

comparing it with standard equation $x^2=4ay$

so 4a=1

$a=\frac{1}{4}$

so Focus of parabola is (0,0)

directrix

y=-a

here $a=\frac{1}{4}$

$y=-\frac{1}{4}$

5 0

3 years ago

Question in picture A) 16/63 B)-16/63 C) 63/16 D) -63/16

Orlov [11]

ANSWER
$\tan(x + y) = - \frac{63}{16}$

EXPLANATION

We were given that,

$\csc(x) = \frac{5}{3}$

This implies that,

$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

$\sin^{2} (x) + \cos^{2} (x)= 1$
to get,

$\cos(x) = \sqrt{1 - ( { \frac{3}{5} })^{2}} = \frac{4}{5}$

We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

$\tan(x + y) = \frac{ \sin(x + y) }{ \cos(x + y) }$

$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

$\tan(x + y) = \frac{ \frac{3}{5} \times \frac{5}{13} + \frac{12}{13} \times \frac{4}{5} }{ \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} }$

$\tan(x + y) = - \frac{63}{16}$

The correct answer is D

4 0

3 years ago

Write the equation of the line shown

Vanyuwa [196]

Answer:

y = $\frac{1}{2}$ x + 1