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pashok25 [27]
3 years ago
9

A 20-ft ladder is 5 feet from the base of a wall. How high up the wall does the ladder reach?

Mathematics
1 answer:
stiks02 [169]3 years ago
7 0
Y = 19.3649. how i worked out the problem is shown below

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Three security cameras were mounted at the corners of a triangular parking lot. Camera 1 was 156 ft from camera 2, which was 101
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Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

Lets use cosine law for finding the angles.

cosA=\frac{b^2+c^2-a^2}{2bc}

cosA=\frac{130^2+156^2-101^2}{2*130*156}

cosA=0.7652

Taking cos inverse

A = 40.08 degrees

Similarly,

cosB=\frac{a^2+c^2-b^2}{2*a*c}

cosB=\frac{101^2+156^2-130^2}{2*156*101}

cosB=0.5597

taking cos inverse

B = 55.97 degrees

Similarly,

cosC=\frac{a^2 +b^2-c^2}{2ab}

cosC=\frac{101^2+130^2-156^2}{2*101*130}

cosC=0.1053

taking cos inverse

C = 83.95 degrees

Means angle C is the largest angles,

So, camera 3 is covering the greatest angle.   :  Answer

Hope it will help :)


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