Is this the whole equation?
Step-by-step explanation:
Cuz if not we need the whole question
Answer: (-2, 2) and (4, 8)
There are two solutions because the two functions cross each other twice.
Step-by-step explanation:
from the first shape bearing of C from D is the angle formed between the north pole and D = 100°
from the second second shape the bearing of C from D is the angle formed between the north pole and D= 235°
Let's call the width of our rectangle
and the length
. We can say
, since the length is equal to 4 cm greater than the width.
Also remember that the perimeter of a rectangle is the sum of two times the width and two times the length, or
. To solve this problem, we can substitute in the information we know, as shown below:
![150 = 2(w + 4) + 2w](https://tex.z-dn.net/?f=150%20%3D%202%28w%20%2B%204%29%20%2B%202w)
![150 = 4w + 8](https://tex.z-dn.net/?f=150%20%3D%204w%20%2B%208)
![142 = 4w](https://tex.z-dn.net/?f=142%20%3D%204w)
![w = \frac{71}{2}](https://tex.z-dn.net/?f=w%20%3D%20%5Cfrac%7B71%7D%7B2%7D)
Now, we can substitute in the width we found into the formula for length, which is
:
![l = \frac{71}{2} + 4](https://tex.z-dn.net/?f=l%20%3D%20%5Cfrac%7B71%7D%7B2%7D%20%2B%204)
![l = \frac{79}{2}](https://tex.z-dn.net/?f=l%20%3D%20%5Cfrac%7B79%7D%7B2%7D)
The width of our rectangle is
cm and the length of our rectangle is ![\boxed{\frac{79}{2} \,\, \textrm{cm}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cfrac%7B79%7D%7B2%7D%20%5C%2C%5C%2C%20%5Ctextrm%7Bcm%7D%7D)
Answer: 90 degrees to 120 degrees
D
Step-by-step explanation: