Solutions
We know that a rectangle has four sides and the perimeter of a rectangle is the distance around the outside of the rectangle.The opposite sides of a rectangle are congruent To find the perimeter you have to use the formula 2 × <span>(Side A + Side B).
</span>
We have the side lengths 7.7 mm and 17.2 mm.
Solve
2 × <span>(Side A + Side B)
2 </span>× <span>( Side A (7.7) + Side B (17.2) )
</span>= (7.7 x 2) + (17.2 x 2)
= 49.6
<span>The perimeter is 49.6 mm². </span>
Answer:
its 16
Step-by-step explanation:
<em>Answer:</em>
<em>2</em>
<em>Step-by-step explanation:</em>
<em>The factors of 72: 1, </em><em>2</em><em>, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72</em>
<em>The factors of 98: 1, </em><em>2</em><em>, 7, 14, 49, 98
</em>
<em>Your greatest common factor is 2.</em>
<em>Hope this helps. Have a nice day.</em>
Answer:
2.5, 6 and 6.5 inches.
Step-by-step explanation:
5 + 12 + 13 = 30
So the shortest side = 5/30 * 15 = 1/6 * 15
= 2.5 inches.
The longest = 13 / 30 * 15 = 13/2
= 6.5 inches,
and the third = 12/30 * 15
= 6 inches.
Answer:
<h2>The circumference is multipled by 4.</h2>
Step-by-step explanation:
The formula of an area of a circle"
![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
The formula of a circumference of a circle:
![C=2\pi r](https://tex.z-dn.net/?f=C%3D2%5Cpi%20r)
The area multipled by 16:
![16A=16\pi r^2\\\\16A=\pi(4^2r^2)\\\\16A=\pi(4r)^2](https://tex.z-dn.net/?f=16A%3D16%5Cpi%20r%5E2%5C%5C%5C%5C16A%3D%5Cpi%284%5E2r%5E2%29%5C%5C%5C%5C16A%3D%5Cpi%284r%29%5E2)
The radius has increased fourfold, therefore:
![C'=2\pi(4r)=4(2\pi r)=4C](https://tex.z-dn.net/?f=C%27%3D2%5Cpi%284r%29%3D4%282%5Cpi%20r%29%3D4C)
The circumference is multipled by 4.
You can calculate the area and check the circumference:
![r=11.6\ in\\\\A=\pi(11.6)^2=132.56\pi\\\\16A=(16)(134.56\pi)=2152.96\pi\ in^2](https://tex.z-dn.net/?f=r%3D11.6%5C%20in%5C%5C%5C%5CA%3D%5Cpi%2811.6%29%5E2%3D132.56%5Cpi%5C%5C%5C%5C16A%3D%2816%29%28134.56%5Cpi%29%3D2152.96%5Cpi%5C%20in%5E2)
Calculate the radius:
<em>divide both sides by π</em>
![r^2=2152.96\to r=\sqrt{2152.96}\\\\r=46.4\ in](https://tex.z-dn.net/?f=r%5E2%3D2152.96%5Cto%20r%3D%5Csqrt%7B2152.96%7D%5C%5C%5C%5Cr%3D46.4%5C%20in)
Calculate the circumference of both circles:
![r=11.6\ in\\\\C=2\pi(11.6)=23.2\pi\ in](https://tex.z-dn.net/?f=r%3D11.6%5C%20in%5C%5C%5C%5CC%3D2%5Cpi%2811.6%29%3D23.2%5Cpi%5C%20in)
![r=46.4\ in\\\\C'=2\pi(46.4)=92.8\pi\ in](https://tex.z-dn.net/?f=r%3D46.4%5C%20in%5C%5C%5C%5CC%27%3D2%5Cpi%2846.4%29%3D92.8%5Cpi%5C%20in)
![\dfrac{C'}{C}=\dfrac{92.8\pi}{23.2\pi}=4\to C'=4C](https://tex.z-dn.net/?f=%5Cdfrac%7BC%27%7D%7BC%7D%3D%5Cdfrac%7B92.8%5Cpi%7D%7B23.2%5Cpi%7D%3D4%5Cto%20C%27%3D4C)