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2 years ago

12

An airplane makes an angle of depression of 23.2° when it descends. It is calculated that the

1 answer:

dem82 [27]2 years ago

4 0

Answer:

im bord so dont delete this

Step-by-step explanation:

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Can somebody please help me out please my grads are bad

Vika [28.1K]

Answer:

a) 10 inches

b) 48 feet

Step-by-step explanation:

10 inches, 60/6 = 10

48 feet, 8*6 = 48

7 0

2 years ago

Help with this one plz!

Alex17521 [72]

What do you need help with?

3 0

2 years ago

Three vertices of parallelogram MNPQ are M(-1,1) , N(2,3) , and P(4,1). Plot points M, N, P, Q in the coordinate plane below.

Karo-lina-s [1.5K]

Made it quickly in WA so you get it fast

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3 years ago

Find the area of quadrilateral ABCD. A. 27.28 units² B. 33.08 units² C. 28.53 units² D. 26.47 units²

Ludmilka [50]

Answer:

<h3> $\boxed{ \boxed{ \bold{ \purple{ \sf{28.53 \: {units}^{2} }}}}}$ </h3>

Option C is the correct option.

Step-by-step explanation:

For ABD

$\sf{ = \frac{2.89 + 8.59 + 8.6}{2} }$

$\sf{ = \frac{20.08}{2} }$

$\sf{ = 10.04}$

∆ ABD = $\sf{ = \sqrt{10.04(10.04 - 2.89)(10.04 - 8.59)(10.04 - 8.6)} }$

$\sf{ = \sqrt{10.04 \times 7.15 \times 1.45 \times 1.44 }}$

$\sf{ = \sqrt{149.8891} }$

$\sf{ = 12.2429}$

For ∆ ACD ,

$\sf{s = \frac{8.6 + 4.3 + 7.58}{2} }$

$\sf{ = \frac{20.48}{2} }$

$\sf{ = 10.24}$

∆ ACD = $\sf{ = \sqrt{10.24(10.24 - 8.6)(10.24 - 4.3)(10.24 - 7.58} }$

$\sf{ \sqrt{10.24 \times 1.64 \times 5.94 \times 2.66} }$

$\sf{ = \sqrt{265.3456} }$

$\sf{ = 16.2894}$

Area of quadrilateral ABCD = $\sf{12.2429 + 16.2894}$

$\sf{ = 28.5323}$

$\sf{ = 28.53}$ units ²

Hope I helped!

Best regards!

8 0

3 years ago

Read carefully and click the option that has the correct answer of the question.

vitfil [10]

Answer:

$67.38 is the correct answer

8 0

3 years ago

Read 2 more answers