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sweet-ann [11.9K]

2 years ago

13

You get a summer job and make a total of $5,500 throughout the summer months. The government takes out taxes from that money at

a rate of 33%. How much money did you really make after taxes were taken out?

1 answer:

bonufazy [111]2 years ago

8 0

Answer:

$1650 is the answer hope it helps

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Angles 1 and 2 form a right angle.Which word describes their measures?

Andreas93 [3]

Answer:

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3 years ago

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aleksley [76]

The length of PR is 4.4 units.

Explanation:

It is given that the length of the hypotenuse is 10 units.

Also, the angle of R is 64°

To find the length of PR, we shall use the cosine formula,

$\cos \theta=\frac{a d j}{h y p}$

Here, $\theta=64$ , adj = PR and hyp = 10

Substituting these values in the formula, we get,

$\cos 64=\frac{P R}{10}$

Multiplying both sides by 10, we get,

$10*\cos 64={P R}$

Substituting the value for cos 64, we get,

$10*0.438={P R}$

Multiplying, we have,

$4.38=PR$

Rounding off, we get,

$PR=4.4$

Thus, the length of PR is 4.4 units.

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3 years ago

What would be the quickest way to complete a rotation of 270 degrees clockwise

givi [52]

Not sure the type of answer you are looking for. Yet 270 degrees is 3/4 of a full turn. (90 x 3)

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3 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

(C) Tan(A + B) = $\frac{Sin(A +B)}{Cos(A + B)}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

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