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saw5 [17]
3 years ago
10

You and your friend each purchased identical subscriptions to an online video rental site. When you joined, you each paid the on

e-time membership processing fee. You also paid a flat rate for each movie that you downloaded. By the end of the first month, you had downloaded 8 movies and paid $16.50, while your friend had downloaded only 6 movies and paid $14.00. What was the amount of the flat fee you paid?
Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:

$1.25

Step-by-step explanation:

Let f equal the flat rate.

Let p equal the one-time membership processing fee.

Start with a system of equations:

16.50=8f+p

14=6f+p

Use the elimination method and multiply your second equation by -1 to cancel out the ps:

-1(14=6f+p)

Now combine the equations:

16.50=8f+p

-14=-6f-p

Subtract:

2.5=2f

Divide by the coefficient of f, which is 2 (I rearranged the equation):

f=1.25

~

Even though we're not solving for the one-time processing fee, to check our work, we'll need to solve for p, so start with the initial system of equations:

16.50=8f+p

14=6f+p

Use the elimination method and multiply the first equation by 3, and the second equation by -4:

3(16.50=8f+p)

-4(14=6f+p)

Multiply:

49.50=24f+3p

-56=-24f-4p

Subtract:

-6.5=-p

Divide by the coefficient of p, which is -1 (Rearranged equation):

p=6.5

~

Check your work:

16.50=8(1.25)+6.5

14=6(1.25)+6.5

Solve:

16.50=16.50

14=14

It's correct!

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Square root of 2tanxcosx-tanx=0
kobusy [5.1K]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3242555

——————————

Solve the trigonometric equation:

\mathsf{\sqrt{2\,tan\,x\,cos\,x}-tan\,x=0}\\\\ \mathsf{\sqrt{2\cdot \dfrac{sin\,x}{cos\,x}\cdot cos\,x}-tan\,x=0}\\\\\\ \mathsf{\sqrt{2\cdot sin\,x}=tan\,x\qquad\quad(i)}


Restriction for the solution:

\left\{ \begin{array}{l} \mathsf{sin\,x\ge 0}\\\\ \mathsf{tan\,x\ge 0} \end{array} \right.


Square both sides of  (i):

\mathsf{(\sqrt{2\cdot sin\,x})^2=(tan\,x)^2}\\\\ \mathsf{2\cdot sin\,x=tan^2\,x}\\\\ \mathsf{2\cdot sin\,x-tan^2\,x=0}\\\\ \mathsf{\dfrac{2\cdot sin\,x\cdot cos^2\,x}{cos^2\,x}-\dfrac{sin^2\,x}{cos^2\,x}=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left(2\,cos^2\,x-sin\,x \right )=0\qquad\quad but~~cos^2 x=1-sin^2 x}

\mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\cdot (1-sin^2\,x)-sin\,x \right]=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2-2\,sin^2\,x-sin\,x \right]=0}\\\\\\ \mathsf{-\,\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}\\\\\\ \mathsf{sin\,x\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}


Let

\mathsf{sin\,x=t\qquad (0\le t


So the equation becomes

\mathsf{t\cdot (2t^2+t-2)=0\qquad\quad (ii)}\\\\ \begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{2t^2+t-2=0} \end{array}


Solving the quadratic equation:

\mathsf{2t^2+t-2=0}\quad\longrightarrow\quad\left\{ \begin{array}{l} \mathsf{a=2}\\ \mathsf{b=1}\\ \mathsf{c=-2} \end{array} \right.


\mathsf{\Delta=b^2-4ac}\\\\ \mathsf{\Delta=1^2-4\cdot 2\cdot (-2)}\\\\ \mathsf{\Delta=1+16}\\\\ \mathsf{\Delta=17}


\mathsf{t=\dfrac{-b\pm\sqrt{\Delta}}{2a}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{2\cdot 2}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{4}}\\\\\\ \begin{array}{rcl} \mathsf{t=\dfrac{-1+\sqrt{17}}{4}}&\textsf{ or }&\mathsf{t=\dfrac{-1-\sqrt{17}}{4}} \end{array}


You can discard the negative value for  t. So the solution for  (ii)  is

\begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{t=\dfrac{\sqrt{17}-1}{4}} \end{array}


Substitute back for  t = sin x.  Remember the restriction for  x:

\begin{array}{rcl} \mathsf{sin\,x=0}&\textsf{ or }&\mathsf{sin\,x=\dfrac{\sqrt{17}-1}{4}}\\\\ \mathsf{x=0+k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=arcsin\bigg(\dfrac{\sqrt{17}-1}{4}\bigg)+k\cdot 360^\circ}\\\\\\ \mathsf{x=k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=51.33^\circ +k\cdot 360^\circ}\quad\longleftarrow\quad\textsf{solution.} \end{array}

where  k  is an integer.


I hope this helps. =)

3 0
3 years ago
Please help ASAP is this correct?
emmasim [6.3K]

Answer:

yess that is correct

Step-by-step explanation:

18<27

7 0
3 years ago
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A statue casts a shadow 30 feet long. At the same time, a person who is 5 feet tall casts a shadow that is 6 feet long. How tall
zmey [24]
Use proportions.

5/6 = x/30

6 * 5 = 30
5 * 5 = 25

x = 25

The statue is 25 feet tall.
3 0
3 years ago
What is the equation of the line that passes through the point (6,4) and has a slope of -2/3
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Answer:

using the given points substitute it into the equation y=mx+c

therefore

y=4

m=-2/3

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c=?

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Step-by-step explanation:

y=mx+c

4=-2/3(6)+c

4=-4+c

c=4+4=8

therefore equation of the graph is y=-2/3X+8

4 0
3 years ago
Mrs.Golden wants to cover her 6.5 by 4 bulletin board with silver paper that comes in 1-foot squares how many squares does Mrs.G
denis-greek [22]

Answer:

26 1-foot squares of silver paper.

Step-by-step explanation:

The dimensions of the bulletin board are  6.5 feet by 4 feet.

To determine how many squares of silver paper she needs to but, we first determine the area of the bulletin board.

Area of the board =6.5 X 4= 26 Square feet

Therefore, Mrs Golden needs to buy <u>26 1-foot squares of silver paper.</u>

There will be <u>no pieces left over</u> as there is no decimal or fractional value in the area of the bulletin board.

6 0
3 years ago
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