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Anton [14]
2 years ago
13

Help me find the area

Mathematics
2 answers:
Marianna [84]2 years ago
8 0

Answer: 15.8 mm

Step-by-step explanation:

67.15*2=134.3

134.3/8.5=15.8

quester [9]2 years ago
5 0

Answer:

7.9

Step-by-step explanation:

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4 cm
pentagon [3]

Answer:

do we have to find area?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
estaba previsto destinar 3/14 de partes de una finca a plazas de aparcamiento pero finalmente han destinado 3/4 de lo previsto a
JulsSmile [24]

Queremos ver que fracción de la finca se ha destinado a plazas de aparcamiento.

La solución es:

La fracción de la finca que se destina a plaas de aparcamiento es 3/56

Sabemos que originalmente se iba a destinar 3/14 del total de la finca a plazas de aparcamiento, pero finalmente se destino 3/4 de lo previsto a zonas ajardinadas.

Es decir, <u>se destino 3/4 de los 3/14 del total de la finca</u> a zonas ajardinadas, entonces <u>el 1/4 restante se dedico a plazas de aparcamiento</u>, esto da:

(1/4)*3/14  = 3/56

La fracción de la finca que se destina a plaas de aparcamiento es 3/56

Sí quieres aprender más, puedes leer:

brainly.com/question/16649102

8 0
3 years ago
Use Cramers Rule to solve the system <br> 2x - 3y = 11<br> -6x + 8y = 34
Nastasia [14]

Step-by-step explanation:

given :

2x - 3y = 11

-6x + 8y = 34

find : the solutions of the system by using Cramers Rule.

solutions:

in the matrix 2x2 form =>

[ 2 -3] [x] [11]

=

[-6 8] [ y] [34]

D =

| 2 -3 |

|-6 8 |

= 8×2 - (-3) (-6)

= 16-18 = -2

Dx = | 11 -3 |

| 34 8 |

= 11×8 - (-3) (34)

= 88 + 102

= 190

Dy = | 2 11 |

|-6 34 |

= 2×34 - (-6) (11)

= 68 + 66

= 134

x = Dx/D = 190/-2 = -95

y = Dy/D = 134/-2 = -67

the solutions = {-95, -67}

8 0
3 years ago
Read 2 more answers
Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t
makkiz [27]

Answer:

Step-by-step explanation:

x + 2y + 3z = 12

z=\frac{12-x-2y}{3}

Volume = V=f(x,y) = xy(\frac{12-x-2y}{3} )

find partial derivatives using product rule

f_x =\frac{y}{3} (12-2x-2y)\\f_y = \frac{x}{3} (12-x-4y)

i.e.

Using maximum for partial derivatives, we equate first partial derivative to 0.

y=0 or x+y =6

x=0 or x+4y =12

Simplify to get y =2, x = 4

thus critical points are (4,2) (6,0) (0,3)

Of these D the II derivative test gives

D<0 only for (4,2)

Hence maximum volume is when x=4, y=2, z= 4/3

Max volume is = 4(2)(4/3) = 32/3

6 0
3 years ago
Find the equation of the line specified. The line passes through the points ( 5, 2) and ( 6, 4) a. y = 2x - 8 c. y = 2x + 12 b.
o-na [289]
<span>( 5, 2) and ( 6, 4)
slope m = (4-2)/(6-5) = 2

y = mx + b
b = y - mx
b = 2 - 2(5)
b = 2 - 10
b = -8

so now you have slope m = 2 and y intercept b = -8

equation
y = 2x - 8

answer
</span><span>a. y = 2x - 8</span>
4 0
3 years ago
Read 2 more answers
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