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3 years ago

Oop- help me;-; please..

Mathematics

1 answer:

VMariaS [17]3 years ago

6 0

Answer:
5c+4=2(c-5)
opening the parentheses we get:
5c+4=2c-10
putting like terms together we get
5c-2c=-10-4
3c=-14
c=-14/3

so the answer would be A. C = - 4 2/3

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Which of the following relations are not functions? Select all that apply

alekssr [168]

A,b,c, d that’s the answer

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3 years ago

Make 2 sets of data 8 numbers each between 1 and 25. Then calculate the median and IQR for each data set.

vlada-n [284]

The median of the data set will be 15.5. The data set is in between the 1 to 25.

<h3>What is median?</h3>

Median is such a number for the arranged data set in ascending or descending order, such that to its left and to its right belong the same number of observations.

The data set between the number is;

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25

The value of IQR for data set is;

First Quartile Q1 = 6.5

Second Quartile Q2 = 13

Third Quartile Q3 =19.5

The median of the data set is;

$\rm Median= \frac{15+16}{2} \\\\ Median= 15.5$

Hence, the median of the data set will be 15.5.

To learn more about median refer:

brainly.com/question/21396105

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3 0

2 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

3 years ago

Find the median of the baseball batting averages.

Charra [1.4K]

Answer:

0.236

Step-by-step explanation:

First put it in order

0.199, 0.211, 0.225, 0.236, 0.257, 0.264, and 0.283

Then find the middle number

0.236

7 0

3 years ago

Read 2 more answers

What is the distance in units from (−4, 18) to (15, 18) on the coordinate place?

alexdok [17]

The answer is 19......................................................................................................................................................................................................................

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3 years ago