Answer: option D. 2x^2 + (3/2)x - 5
Explanation:
1) polynomials given:
f(x) = x/2 - 2 and g(x) = 2x^2 + x - 3
2) question: find (f + g) (x)
That means that f(x) + g(x), so you have to add up the two polynomials given.
3) x/2 - 2 + 2x^2 + x - 3
4) Combine like terms:
a) terms with x^2: you only have 2x^2, so it is not combined with other term.
b) terms with x: x/2 + x
that is a sum of fractions: x/2 + x = [x + 2x] / 2 = 3x / 2 = (3/2)x
c) constant terms: - 2 + (-3) = - 2 - 3 = - 5
5) Result: 2x^2 + (3/2)x - 5
That is the option d.
Answer:
12 and 24
Step-by-step explanation:
2 numbers, x in this case, with one being twice the other, one of them will be 2x, equals 36. Your equation would look like this: 2x+x=36. Simplify it to get 3x=36, divide the 3 and you get 12. 12 will be your small number then multiply by 2 to get your large one, 24.
It is somewhere in between 7,4 and 4,8
Df = g - 10
To solve for d, divide both sides by f.
df / f = (g - 10) / f
d = (g - 10) / f
I hope this explains it.
Since the variable x has an invisible one next to it, which is 1x, it is 6x.
