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antoniya [11.8K]
3 years ago
5

What is the solution set for the inequality 6x-7>5

Mathematics
1 answer:
zhenek [66]3 years ago
3 0
Rearrange equation to get
6x>12 so
x>2
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Juliette and her two borthers spent $45.75 on flowers for their grandmother.
enyata [817]
45.75/3= 15.25

(45.75-15)/3= 10.25


A= $15.25

B=$10.25
4 0
4 years ago
Does anyone know how to find the area of the shaded region?
Rzqust [24]
Find the area of the rectangle with the circles. Then find the area of each of the circles and add them together and minus that from the rectangle’s area.

A of rectangle = 30x10 = 300
A of circle = pi x r squared = pi x 25
A of shaded region = 300 - 75 pi = 68.3805cm square
6 0
4 years ago
Why did I get it wrong ? I’m finding constant B and idk what’s wrong with my step.
Klio2033 [76]

Answer:

\large \boxed{\sf \ \ A=5, \ \ B=-13 \ \ }

Step-by-step explanation:

Hello,

What you did is correct...

(Ax-3)(x-2)=5x^2+Bx+6\\\\\text{*** we develop the left side ***}\\\\Ax^2+(-2A-3)x+6=5x^2+Bx+6

... and you found A by identifying the term in x^2 to get A = 5, right?

<u>What about the other terms?</u>

<u />

We can then identify the like terms:

>>> term in x^2\\

   A = 5

>>> term in x

   -2A+3=B

>>> constant term

   6 = 6

As we know that A=5 it means that B = -2*5-3=-13

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
4 years ago
Read 2 more answers
Another question this math is not my favorite ? Struggling but son what understanding it . Help please
Evgen [1.6K]
12/3= 4 <-- This equation shows that one box will benefit 4 children.
24/4=6 <-- This equation shows how many boxes will benefit 24 children.

Therefore, Raymond should buy 6 boxes.
5 0
3 years ago
g A catering service offers 7 %E2%80%8b Appetizers, 9 main%E2%80%8B courses, and 5 desserts. A banquet committee is to select 2
Feliz [49]

Answer:

945 ways

Step-by-step explanation:

<u>Total</u>

  • Number of Appetizers = 7
  • Number of main courses = 9
  • Number of desserts =5

<u>Required Selection</u>

  • Number of Appetizers = 2
  • Number of main courses = 8
  • Number of desserts =4

2  Appetizers out of 7 can be selected in ^7C_2 ways

8 main courses out of 9 can be selected in ^9C_8 ways

4 desserts out of 5 can be selected in ^5C_4 ways

Therefore, the number of ways this can be done

=^7C_2 \times ^9C_8 \times ^5C_4

=945 ways

5 0
3 years ago
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