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2 years ago

What is the measure of angle DCE? Use numbers only.

Mathematics

1 answer:

Zarrin [17]2 years ago

4 0

Answer:

156 degrees

Step-by-step explanation

First we need to figure out what X is. To do that we set up the equation 7x+3=8x because vertical angles are congruent. After solving that we get x=3. We plug 3 back into each equation and we get that angle ACE equals 24. Since angle ACE and angle DCE are supplementary we know that they will equal 180 so we subtract 24 from 180 and get 156 as the final answer.

Hope this helps!

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How do you solve this system by elimination?

zimovet [89]

(-5x+7y=11) - (-5x+3y=19) =
4y = -8. (divide both sides by 4)

y = -2

Substitute

-5x + 7(-2) =11
-5x - 14 =11
-5x = 25

x = -5

y = -2 and x = -5

8 0

3 years ago

One-quarter of the counters in a tub are red. The rest of the counters are green. If there are 48 green counters, how many red c

scZoUnD [109]

There are 16 red counters there.

<h3>Fractions and proportions</h3>

If one-quarter of the counters in a tub are red and the rest are green, then there are three-quarter of the counter in the tub.

Let the total counter be x such that

3/4x = 48

3x = 4 * 48

x = 4 * 16

x = 64

Determine the amount of red counter

Red counter = 64 - 48

Red counter = 16

Hence there are 16 red counters there.

Learn more on proportion here; brainly.com/question/1496357

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6 0

2 years ago

What is32,432 rounded to the nearest thousand

Damm [24]

The answer would be 32,000.

5 0

3 years ago

Read 2 more answers

PLEASE HELP

Lostsunrise [7]

Answer:

is there a visual version of this question?

3 0

2 years ago

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PLEASE HELP! I ONLY HAVE 15 MINS! WILL MARK BRAINLIEST! 20 POINTS! Suppose N coins lie heads up on a table. In one turn, you can

Romashka [77]

Answer: it is only possible if N = 2.

Step-by-step explanation:

if you have N heads up coins.

turn one, you turn N -1 coins up.

Now you have N - 1 coins tails up and one coin heads up.

Second turn, you turn N - 1 coins, (if you select the same N - 1 coins as before, you will end in the initial situation, so now we will change one coin, this time we will select the coin that is still heads up and we will leave one of the tails up unchanged)

Then we have N - 2 coins heads up and 2 coins tails up.

Now, we can select any N -1 coins to flip, and we will end with with N - 1 coins tail up and 1 coin heads up.

and this cycle will repeat.

Then the only situation is having N = 2.

Becuase when we have N -2 coins heads up and 2 coins tails up we will have: N - 2 = 0, so we have 0 coins heads up and 2 coins tails up.

This means that the statement is only true if N = 2.

6 0

2 years ago