The solution to the first expression - 7+3(9-4)^2÷5 is given as 22.
To get the answer correctly, one must follow rudimentary rules of operations which are coined into the acronym BODMAS.
<h3>What is BODMAS?</h3>
This is the order in which mathematical operations must be executed.
B = Bracket
O = Orders (that is Powers, Indices or roots)
D= Division
M = Multiplication
A = Addition
S = Subtraction
Now lets see how we got 22 from the first set of operations:
<h3>Operation 1 (Example)</h3>
7+3(9-4)^2÷5 =
7+3 (5)^2÷5=
7+3 * 25÷5 =
7+3*5=
7+15=
22
Following the BODMAS rule and the example in Operation 1 above, we can state the remaining answers as follows:
<h3>
Operation 2</h3>
12/3-4+7^2 = 49
<h3 /><h3>
Operation 3</h3>
(7-3)×3^3÷9 = 12
<h3>Operation 4</h3>
5(7-3)^2÷(6-4)^3-9 = 1
<h3>Operation 5</h3>
3×(7-5)^3÷(8÷4)^2-5 = 1
<h3>Operation 6</h3>
9+(3×10)/5×2-12 = 9
See the link below for more about Mathematical Operations:
brainly.com/question/14133018
We substitute the given into the equation
given: a=-1, b=2, c=

=(

-1
=

-1
=

-1
=

-1
to continue, we can either find a common denominator or change the fraction to decimal.
Fraction to Decimal:

=-2.5
Equation=-2.5-1=-3.5
OR Common Denominator:
=


×

(denominator should be -2=common)
=

+

=

which also = to -3.5
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Answer
16/43
Step-by-step explanation:
17 Male + 27 female = 44 students
now n= 2 so first student was male so one male student was taken out of the equation so 16 male left. now left male students by remaining students so now total left students = 43
so, prob = remaining males/remaining students=16/43
Answer:
+3
Step-by-step explanation:
if your subtracting a negitive it means your adding and its now a positive