Question

Can someone help me please?

Answer 1

Answer:

1) x = 3, y = 2 or (3, 2)

2) x = 0, y = 2 or (0, 2)

6) x = 3, y = – 4 or (3, – 4)

Step-by-step explanation:

I will only provide solutions for questions 1, 3, and 6 in accordance with Brainly's guidelines.

Question 1:  

$\displaystyle\mathsf{\left \{ {{\:\:Equation\:1:\:y\:=\:-2x\:+\:5} \atop{Equation\:2:\:y\:=\:-x\:+\:2}} \right. }$  

Substitute the value of y in equation 2 into the first equation:

y = -2x + 5

-x + 2 = -2x + 5

Add 2x on both sides:

-x + 2x + 2 = -2x + 2x + 5

x + 2 = 5

Subtract 2 from both sides to isolate x:

x + 2 - 2 = 5 - 2

x = 3

Substitute the value of x into Equation 2 to solve for the value of y:

y = -x + 5

y = -(3) + 5

y = 2

Solution of the given systems of linear equations:

Therefore, the solution to the given systems of linear equations is: x = 3, y = 2 or (3, 2).

Question 3:

$\displaystyle\mathsf{\left \{ {{Equation\:1:\:3x\:+\:5y=\:10} \atop{Equation\:2:\:y\:=\:-5x\:+\:2}} \right. }$

Substitute the value of y from Equation 2 into Equation 1:

3x + 5y = 10

3x + 5(-5x + 2) = 10

Distribute 5 into the parenthesis:

3x + -25x + 10 = 10

Combine like terms:

-22x + 10 = 10

Subtract 10 from both sides:

-22x + 10 - 10 = 10 - 10

-22x = 0  

Divide both sides by -22 to solve for x:

$\displaystyle\mathsf{\frac{-22x}{-22}\:=\:\frac{0}{-22}}$

x = 0

Substiute the value of x into Equation 2 to solve for y:

y = -5x + 2

y = -5(0) + 2

y = 2

Solution of the given systems of linear equations:

Therefore, the solution to the given systems of linear equations is: x = 0, y = 2 or (0, 2).

Question 6:

$\displaystyle\mathsf{\left \{\quad\:Equation\:1:\:-2x+6y=\:-30} \atop{Equation\:2:\:y-2x=\:-10}} \right.}$

Add 2x to both sides of Equation 2 to isolate y:

y – 2x = –10

y – 2x + 2x = 2x – 10

y = 2x – 10

Substitute the value of y from the previous step into Equation 1:

– 2x + 6y =  – 30

– 2x + 6(2x – 10) =  – 30

Distribute 6 into the parenthesis:

– 2x + 12x  – 60 =  – 30

Combine like terms:

10x – 60 =  – 30

Add 60 to both sides:

10x – 60 + 60 =  – 30 + 60

10x = 30

$\displaystyle\mathsf{\frac{10x}{10}\:=\:\frac{30}{10} }$

x = 3

Substitute the value of x into Equation 2 to solve for y:

y – 2x = –10

y – 2(3) = –10

y – 6 = –10

y – 6 + 6 = –10 + 6

y = – 4

Solution of the given systems of linear equations:

Therefore, the solution to the given systems of linear equations is: x = 3, y = – 4 or (3, – 4).