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dangina [55]
3 years ago
15

PLEASEEEE HELPPPP ASAPPPP

Mathematics
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

x ≈ 7.1

Step-by-step explanation:

Using the cosine ratio in the right triangle.

cos27° = \frac{adjacent}{hypotenuse} = \frac{KL}{KM} = \frac{6.3}{X} ( multiply both sides by x )

x × cos27° = 6.3 ( divide both sides by cos27° )

x = \frac{6.3}{cos27} ≈ 7.1 ( to the nearest tenth )

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the relationship between altitude and the boiling point is linear.AT an altitude of  8300ft 8300 ft , the liquid 
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Complete Question

The  relationship  between  altitude  and  the  boiling  point  is  linear. At  an  altitude  of   8300ft, the  liquid  boils  at   194.23 °  F

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Write  an  equation  giving  the  boiling  point   b  of  the  liquid,  in  terms  of  altitude  a  in   feet . feet . What  is  the  boiling  point  of  the  liquid  at   2600ft

Answer:

The equation is  y  =  -0.001943x + 210.3569

At  2600ft  the temperature is  y  =  205.3051 \  °F

Step-by-step explanation:

From the question we are told that

    The temperature at 8300ft is 194.23 °  F

    The  temperature at 4200 ft is 202.02° F

Generally the slope for this relationship is mathematically represented as

      m  =  \frac{ 202.2 - 194.23}{ 4200 - 8300}

=>     m  = 0.001943  ^o  F / ft  

Generally the according to the point slope formula is

      y - y_1  =  m(x -x_1 )

=>   y - 194.23 =  -0.001943 (x - 8300 )

=>  y - 194.23 =  -0.001943x + 16.1269

=>  y  =  -0.001943x + 210.3569

Now we are given from the question that   x =  2600 ft

Then  

         y  =  -0.001943(2600) + 210.3569

=>      y  =  205.3051 \  °F

   

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