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Ann [662]
2 years ago
5

What is the standard form of the polynomial 4x+6y^3x-xy+xy^2

Mathematics
1 answer:
meriva2 years ago
7 0

The required standard form is 6y^3x+xy^2-xy+4x

<h3>Polynomial function</h3>

Given the polynomial function expressed as:

  • 4x+6y^3x-xy+xy^2

We are to express this polynomial in standard form

To do that, we will write the degrees of the variables in descending order of magnitude as shown:

4x+6y^3x-xy+xy^2\\6y^3x+xy^2-xy+4x

Hence the required standard form is 6y^3x+xy^2-xy+4x

Learn more on polynomial functions here: brainly.com/question/7693326

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hram777 [196]

Answer:

241/20

Step-by-step explanation:

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3 years ago
Evaluate each expression for the given value(s)
Butoxors [25]

Answer:

-16

Step-by-step explanation:

Substitute the values into the equation

=  \frac{ ({ - 12 + 4}^{2}) }{ - 4}  \\  = \frac{ {( - 8)}^{2} }{4}  \\  = \frac{64}{4}  \\  =  - 16

<h2><em>OladipoSeun</em><em>♡˖꒰ᵕ༚ᵕ⑅꒱</em></h2>

4 0
3 years ago
The velocity,v of a missile is related to time t, By the equation v=5t^2+3t+1.calculate the time at which the velocity is minimu
Cloud [144]

Answer:

  • time: t = -0.3
  • minimum: v = 0.55

Step-by-step explanation:

For quadratic ax^2 + bx + c, the extreme value is found at x=-b/(2a). For your quadratic, the minimum is found at ...

  t = -(3)/(2(5))

  t = -0.3 . . . . . time of minimum velocity

__

The value of velocity at that time is ...

  v = 5(-0.3)^2 +3(-0.3) +1 = 5(.09) -.9 +1

  v = 0.55 . . . . . value of minimum velocity

3 0
3 years ago
Which is the equation for ---
ratelena [41]
Equation of the line: 
y=mx+b
Ordinate at the origin (where the line cut the y-axis): b=1

B=(-5,5)=(xb,yb)→xb=-5, yb=5
C=(0,1)=(xc,yc)→xc=0, yc=1
m=(yc-yb)/(xc-xb)
m=(1-5)/(0-(-5))
m=(-4)/(0+5)
m=(-4)/(5)
m=-(4/5)

y=mx+b
y=-(4/5)x+1
Multiplying the equation by 5:
5[y=-(4/5)x+1]
5y=-4x+5
Adding 4x both sides of the equation:
5y+4x=-4x+5+4x
4x+5y=5

Answer: The equation for BC is: Third option 4x+5y=5
7 0
2 years ago
Which dimensions cannot create a triangle?
podryga [215]

Answer:

three angles measuring 109º, 25º, and 145º cannot create a triangle

three angles measuring 40º, 70º, and 65º cannot create a triangle

Step-by-step explanation:

<u><em>Verify each dimensions</em></u>

Part 1) three angles measuring 109º, 25º, and 145º

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

In this problem we have

109^o+25^o+145^o=279^o

279^o> 180^o

therefore

three angles measuring 109º, 25º, and 145º cannot create a triangle

Part 2) three sides measuring 9 m, 15 m, and 9 m

we know that

The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Applying the triangle inequality theorem

1) 9+15 > 9 ---> is ok

2) 9+9 > 15 ---> is ok

therefore

three sides measuring 9 m, 15 m, and 9 m can create a triangle

Part 3) three angles measuring 40º, 70º, and 65º

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

In this problem we have

40^o+70^o+65^o=175^o

175^o< 180^o

therefore

three angles measuring 40º, 70º, and 65º cannot create a triangle

Part 4) three sides measuring 6 cm, 8 cm, and 10 cm

we know that

The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Applying the triangle inequality theorem

1) 6+8 > 10 ---> is ok

2) 8+10 > 6 ---> is ok

3) 6+10 > 8 ---> is ok

therefore

three sides measuring 6 cm, 8 cm, and 10 cm can create a triangle

4 0
2 years ago
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