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Ann [662]
2 years ago
5

What is the standard form of the polynomial 4x+6y^3x-xy+xy^2

Mathematics
1 answer:
meriva2 years ago
7 0

The required standard form is 6y^3x+xy^2-xy+4x

<h3>Polynomial function</h3>

Given the polynomial function expressed as:

  • 4x+6y^3x-xy+xy^2

We are to express this polynomial in standard form

To do that, we will write the degrees of the variables in descending order of magnitude as shown:

4x+6y^3x-xy+xy^2\\6y^3x+xy^2-xy+4x

Hence the required standard form is 6y^3x+xy^2-xy+4x

Learn more on polynomial functions here: brainly.com/question/7693326

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HELP ILL GIVE BRAINLIEST :(
liraira [26]

Answer:

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4 0
2 years ago
Plz answer this question:
d1i1m1o1n [39]

Yes, Lord Vader !

                                               2/3 x + 5   = 1/2

Multiply each side by  2 :       4/3 x + 10  =  1

Multiply each side by  3 :         4  x + 30  =  3  <== equivalent equation
                                                                                without fractions
 
Subtract  30  from each side:  4x             =  -27

Divide each side by  4 :            x              =  -27/4  =  -6.75 

6 0
3 years ago
Which is the solution to the equation 1/4x-1/8=7/8+1/2x
timofeeve [1]

Answer:

x = -4

Step-by-step explanation:

Step 1: Subtract 1/2x on both sides

-1/4x - 1/8 = 7/8

Step 2: Add 1/8 on both sides

-1/4x = 1

Step 3: Divide both sides by -1/4

x = -4

4 0
3 years ago
Read 2 more answers
What is the difference of the rational expressions below? 2/x-2 - 3/x
VashaNatasha [74]

Answer: \frac{6-x}{x^{2}-2x}

Step-by-step explanation:

Find the least common multiple (LCM) of the denominators. This is:

LCM=x(x-2)

Divide the LCM by each denominator and multiply the result by each numerator, then you obtain:

\frac{2x-3(x-2)}{x(x-2)}

Apply the distributive property, then you obtain:

\frac{2x-3x+6}{x^{2}-2x}

Add like terms, then you obtain:

\frac{6-x}{x^{2}-2x}

8 0
3 years ago
Read 2 more answers
Would like this problem broken down step by step thanks!
antiseptic1488 [7]

Answer:

m=12

Explanation:

Given any quadratic function, y=ax²+bx+c.

We can determine the nature of the roots of such quadratic function by examining the discriminant, D where:

D=b^2-4ac

• If D>0, the roots are real and unequal.

,

• If D=0, the roots are real and equal.

,

• If D<0, the roots are complex.

In our given equation:

\begin{gathered} y=18x^2+mx+2 \\ a=18,b=m,c=2 \end{gathered}

For the function to have exactly one zero, the value of D=0.

\begin{gathered} D=b^2-4ac=m^2-4(18)(2)=m^2-144 \\ D=0\implies m^2-144=0 \\ Add\text{ 144 to both sides.} \\ m^2=144 \\ Take\text{ the square root of both sides} \\ \sqrt{m^2}=\sqrt{144} \\ m=12 \end{gathered}

The value of m for which the function will have one zero is 12.

4 0
1 year ago
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