Answer:
c is correct.
Step-by-step explanation:
First we simplify the expressions of the parties, and when we get to the two fractions, we multiply the cross, and the answer is obtained.
![\frac{89}{2725} > \frac{1989}{2500000} \\ \\ \\ 89 \times 2500000 > 1989 \times 2725 \\ \\ 222500000 > 5420025](https://tex.z-dn.net/?f=%20%5Cfrac%7B89%7D%7B2725%7D%20%20%3E%20%20%5Cfrac%7B1989%7D%7B2500000%7D%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%2089%20%5Ctimes%202500000%20%3E%201989%20%5Ctimes%202725%20%5C%5C%20%20%5C%5C%20222500000%20%3E%20%205420025)
It should be noted that with a few quick calculations the correct option was reached.
Answer: .33 repeating
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
Answer:
Stan needs about 50 of the 39 cm x 39 cm tiles
or about 155 of the 18 cm x 27 cm tiles
Step-by-step explanation:
Since we are asked to consider only matters of area, we need to calculate first, the area of the patio:
Patio area = 3 m x 2.5 m = 7.5 m^2
Now we consider what surface (in square meters - m^2) each type of tiles cover:
a) for the 39 cm x 39 cm tiles: 0.39 m x 0.39 m = 0.1521 m^2
b) for the 18 cm x 27 cm tiles: 0.18 m x 0.27 m = 0.0486 m^2
Therefore, to cover the area of the patio, the number of tiles type "a" needed is given by the quotient:
7.5 m^2 / 0.1521 m^2 = 49.3096 (about 50 tiles)
while for type "b" tiles the quotient gives:
7.5 m^2 / 0.0486 m^2 = 154.32 (about 155 tiles)