The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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Answer:
wheres your graph?
Step-by-step explanation:
i could do this with a graph lol
12.3 meters because of the 10 meters she jumped plus the 2.3 she went down equals 10+2.3=12.3
Answer:
Infinitely many solutions.
Step-by-step explanation:
4(x-8)+9=4x-23
4x-32+9=4x-23
4x-23=4x-23
infinitely many solutions.
- <em>c.</em><em>)</em><em> </em><em>x</em><em>=</em><em>2</em>
<h2><em>hope</em><em> it</em><em> helps</em><em>!</em></h2>
