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boyakko [2]
2 years ago
14

The complementary base pairs for the DNA strands given. CCC-GGG-TAT-GCA-TGT

Biology
1 answer:
djyliett [7]2 years ago
5 0

Answer:

GGG-CCC-ATA-CGT-ACA

Explanation:

Cytosine pairs with Guanine

Adenine pairs with Thymine

Mnemonic to help you remember: The Car is the the Garage, Apples are on the Tree.

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What is another name for<br> Brucellosis?<br> A. BVD<br> B. Bangs<br> C. Brahms<br> D. IPV
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Answer:

\boxed {\boxed {\sf Answer -\ Option\  B.\ Bangs }}

Explanation:

Brucellosis spreads from infected animals with the disease, or from any unpasteurized milk from cows who may have the disease. It is a very rare disease in the United States. Brucellosis can also be called Bangs.

The answer is Option B. Bangs. Best of Luck!

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In somatic cells, replication of a parent cell results in ___.
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D identical diploid daughter cells

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A cell come a certain organism has 64 individual, or 32 pairs, of chromosomes. Which of these can you draw?
Dmitriy789 [7]

Answer:

B. The cell cannot be a human

Explanation:

Humans have 23 pairs of chromosomes, or 46 individual chromosomes. Mutations in humans usually cause there to be a single extra chromosome, or a single missing chromosome. A mutation would not cause there to be 64. So, A cannot be true. Prokaryotic cells usually have one chromosome, not 64, so C cannot be true. D cannot be assumed as you cannot tell if there is uncontrolled cell growth. Therefore, the answer would be B.

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1 year ago
Animals store most of their excess energy reserves as_____,and this is explained because______.
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3 years ago
Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of
Elodia [21]

Answer:

\boxed {\boxed {\sf 121.905 \ J  }}

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

q= mc \Delta T

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C

Substitue the values into the formula.

q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)

Multiply the first numbers together. The grams will cancel.

q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)

Multiply again, this time the degrees Celsius cancels.

q= 121.905 \ J

<u>121.905 Joules</u> are required.

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2 years ago
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