The average speed between t = 1.0 s and t = 4.0 s will be 2.1+0.3 which is 2.4m/s
<h3>
Velocity function </h3>
Given the equation for the position of the mouse expressed as:

The velocity of the particle is expressed as:

Given that p = 0. 40 m/s and q = -1. 10 m/s, the equation will become:

If the time is <em>t = 1.0 s, the velocity will be:</em>

Similarly if t = 4.0ssec, hence:

The average speed between t = 1.0 s and t = 4.0 s will be 2.1+0.3 which is 2.4m/s
<em>Learn more on</em><em> average speed </em><em>here: brainly.com/question/4931057</em>
Complete question
<em>A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt 2+qt, with p = 0.40 m/s2and q = -1.10 m/s . Determine the mouse's average speed between t = 1.0 s and t = 4.0 s. I have tried everything and the answer is not 0.40 m/s</em>
First calculate the change in y over the change in x:
by - ay -1 - 1 -2
———— = ——— = —— = 1
bx - ax -2 - 0 -2
The slope is 1:
Second set up the equation in y = mx + b form (m is your slope!) ...
y = (1)x + b
... and plug in either point you have used (A or B)
A(0,1)
1 = (1)(0) + b
1 = b
Now you have your equation: y = 1x + 1
Your final step is to plug in point C to solve for your missing variable:
y = (1)(5) + 1
y = 6
the value of H therefore is 6