Question

You are given a sample of metal and asked to determine its specific heat. you weigh the sample and find that its weight is 28.4 n. you carefully add 1.25 x 104 j of heat energy to the sample and find that its temperature rises to 18.0 °c. what is the sample’s specific heat?

Answer 1

The specific heat of the given sample of metal is 14.32 J/kg.K.

What is the Specific heat of a sample?

The specific heat of a sample is the amount of heat needed or required to raise the temperature of that sample by 1K. It is given by the formula:

Q = mCΔT

where;

• Q = Heat transferred
• m = Mass of the substance
• C = Specific heat
• ΔT= Change in temperature.

Recall that:

weight of a substance = mass × gravity

• mass = 28.4 N/ 9.8 m/s²
• mass = 3 N/m/s² = 3 kg

From the equation:

Q = mCΔT

$\mathbf{C = \dfrac{1.25 \times 10^4 \ J}{3 \ Kg \times 291 \ K }}}$

C = 14.32 J/kg.K

Learn more about specific heat here:

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