All categories

2 years ago

There is a bag filled with 4 blue, 3 red and 5 green marbles.

Mathematics

1 answer:

Vsevolod [243]2 years ago

7 0

<h2>The chances of receiving two greens are 5/31.</h2>

Given a bag containing four blue, three red, and five green marbles, the total result is:

Total number of balls = 4 + 3 + 5 = 12

If green is chosen first, the chances of picking a green are 5/12.

The probability that the second stone is green is 4/11 if it is picked and not replaced (4 greens remaining)

The chance of earning two greens is 5/12 4/11.

The chance of getting two greens is 20/132.

The chance of earning two greens is 5/31.

<h3>As a result, the chance of getting two greens is 5/31.</h3>

You might be interested in

Is triangle prq equal to triangle Xyz ? If so, name which similarity postulatebor theorem applies.

Salsk061 [2.6K]

Answer:

I'm not sure for my answer 'cuz I just learned this but i think its A because even though the size changes, the corresponding angle measure are the same and the corresponding sides are proportional.

(Tell me if I'm wrong.)

3 0

3 years ago

Read 2 more answers

Determine a series of transformations that would map Figure RR onto Figure SS.

nadezda [96]

Answer:

transformation

Step-by-step explanati

3 0

3 years ago

Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro

Neporo4naja [7]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ Sanya has a piece of land which is in the shape of a rhombus.

★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.

★ Perimeter of land = 400 m.

★ One of the diagonal = 160 m.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Area each of them [son and daughter] will get.

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Let, ABCD be the rhombus shaped field and each side of the field be $x$

[ All sides of the rhombus are equal, therefore we will let the each side of the field be $x$ ]

Now,

• Perimeter = 400m

$\longrightarrow \tt AB+BC+CD+AD=400m$

$\longrightarrow \tt x + x + x + x=400$

$\longrightarrow \tt 4x=400$

$\longrightarrow \tt \: x = \dfrac{400}{4}$

$\longrightarrow \tt x= \red{100m}$

$\therefore$ Each side of the field = 100m.

Now, we have to find the area each [son and daughter] will get.

So, For $\triangle$ ABD,

Here,

• a = 100 [AB]

• b = 100 [AD]

• c = 160 [BD]

$\therefore \tt Simi \: perimeter \: [S] = \boxed{ \sf \dfrac{a + b + c}{2} }$

$\longrightarrow \tt S = \dfrac{100 + 100 + 160}{2}$

$\longrightarrow \tt S = \cancel{ \dfrac{360}{2}}$

$\longrightarrow \tt S = 180m$

Using herons formula,

$\star \tt Area \: of \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star$

where

• s is the simi perimeter = 180m

• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.

Putting the values,

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(80)(80)(20) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180 \times 80 \times 80 \times 20 }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{9 \times 20 \times 20 \times 80 \times 80}$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{ {3}^{2} \times {20}^{2} \times {80}^{2} }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = 3 \times 20 \times 80$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \red{ 4800 \: {m}^{2} }$

Thus, area of $\triangle$ ABD = 4800 m²

As both the triangles have same sides

So,

Area of $\triangle$ BCD = 4800 m²

Therefore, area each of them [son and daughter] will get = 4800 m²

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

${\underline{\rule{290pt}{2pt}}}$

7 0

1 year ago

Read 2 more answers

Someone please help me

kap26 [50]

Answer:

The answer is x = 4

Step-by-step explanation:

1. First you need to distribute the 3/4 * (x + 8). This looks like (3/4) * (x) + (3/4) * (8) = 9

2. Next you simplify the distributed equation, 3/4x + 6 = 9

3. Now subtract 6 from both sides, 3/4x = 3

4. Multiply both sides by 4/3, 4/x * 3/4x = 3 * 4/3

5. Simplify, x = 4

8 0

3 years ago

Systems of equations, solve by substitution please! x + 7y = -37 4x - 3y = 7

Svetradugi [14.3K]

Answer:

1. x = -37 - 7y

2. x = 7+3y/4

5 0

2 years ago

Read 2 more answers