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2 years ago

144 dollars

Mathematics

1 answer:

kotegsom [21]2 years ago

6 0

Answer:

The correct answer is b

Step-by-step explanation:

54×6×2

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PLS HELP ASAP GIVING BRAINLIEST TO RIGHT AWNSER

egoroff_w [7]

It's C, just look at where the points are.

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3 years ago

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What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

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4 years ago

What number makes the equation true? Enter the answer in the box.<br> - 5 = 9

leonid [27]

Answer:

Step-by-step explanation:

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3 years ago

Let f(x) = 3x + 2 and g(x) = 4–5x. Find f(x) + g(x)

Vadim26 [7]

Answer:

-2x + 6

Step-by-step explanation:

Step 1: Define

f(x) = 3x + 2

g(x) = 4 - 5x

Step 2: Find f(x) + g(x)

3x + 2 + 4 - 5x

-2x + 6

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3 years ago

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How do you convert the general equation form of a circle to standard form? Answer correctly to get 20 points. Please provide an

ivanzaharov [21]

Answer:

Step-by-step explanation:

The standard form of a circle's equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius. To convert an equation to standard form, you can always complete the square separately in x and y.

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