9/20.... Also is the worksheet you’re working on?
For this case we have the following functions:

To find the algebraic solution we must equal both equations.
We have then:

Clearing x we have:

Then, the ordered pair solution is:
Answer:
(x, y) = (2/3, 2)
See attached image.
<span>Give that </span>t<span>he frequency of G5 is 783.99 Hz.
To find the frequency of the note that is a perfect fifth above G5, we recall that </span>the frequencies of notes that are a 'perfect'
fifth apart are in the ratio of 1.5
i.e. <span>the frequency of the note that is a perfect fifth above G5 divided by </span><span>t<span>he frequency of G5 equal 1.5
Let the </span></span><span><span>frequency of the note that is a perfect fifth above G5 be F, then
F / </span>783.99 = 1.5
F = 1.5 x 783.99 = 1175.99
Therefore, </span>the <span>frequency of the note that is a perfect fifth above G5</span> is 1175.99 Hz