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Liula [17]
2 years ago
15

Circles are described below by the coordinates of their centers, C, and one point on their circumference, A. Determine an equati

on for each circle in center-radius form.
(a) C(5,2) and A(11,10)
(b) C(-2,-5) and A(3,-17)
(c) C(5,-1) and A(-2,-5)
Mathematics
1 answer:
Art [367]2 years ago
4 0

Using the given center and point at the circumference, the equation of the circles are:

  • a) (x - 5)^2 + (y - 2)^2 = 100
  • b) (x + 2)^2 + (y + 5)^2 = 169
  • c) (x - 5)^2 + (y + 1)^2 = 65

<h3>What is the equation of a circle?</h3>
  • The equation of a circle of radius r and center (x_0,y_0) is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

Item a:

  • Center C(5,2), hence x_0 = 5, y_0 = 2.

The point at the circumference is A(11,10), hence:

(x - 5)^2 + (y - 2)^2 = r^2

(11 - 5)^2 + (10 - 2)^2 = r^2

r^2 = 100

Hence:

(x - 5)^2 + (y - 2)^2 = 100

Item b:

  • Center C(-2,-5), hence x_0 = -2, y_0 = -5.

The point at the circumference is A(3,-17), hence:

(x + 2)^2 + (y + 5)^2 = r^2

(3 + 2)^2 + (-17 - 5)^2 = r^2

r^2 = 169

Hence:

(x + 2)^2 + (y + 5)^2 = 169

Item c:

  • Center C(5,-1), hence x_0 = 5, y_0 = -1.

The point at the circumference is A(-2,-5), hence:

(x - 5)^2 + (y + 1)^2 = r^2

(-2 - 5)^2 + (-5 + 1)^2 = r^2

r^2 = 65

Hence:

(x - 5)^2 + (y + 1)^2 = 65

You can learn more about equation of a circle at brainly.com/question/24307696

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Answer:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.1)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=5, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(Y)=(nCy)(p)^y (1-p)^{n-y}

Where (nCx) means combinatory and it's given by this formula:

nCy=\frac{n!}{(n-y)! y!}

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

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Answer:

a)D= 0.625 Decimal that describes the portion of the workday he has finished

b)P= D*100= 0.625*100=62.5%

P: percentaje

D: Decimal

Step-by-step explanation:

Nomenclature

F: fraction of daily workday

D: decimal of daily workday

P: percentage of daily workday

Formulas

F= a/b

D= a÷b

P= D*100

Problem development

We have:

F = 5/8, then:

D= 5÷8= 0.625

To obtain the percentage of the workday that Matew has completed, we multiply the decimal x 100

P= 0.625*100=62.5%

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