<u>Answer-</u>
An angle is labeled with either one capital letter or three capital letters
<u>Solution-</u>
<em>Point-</em>
As a point is 0 dimensional, so you just need 1 point to define a point.
<em>Line- </em>
As a line is 1 dimensional,so you need 2 points to define a line.
<em>Plane-</em>
A plane is 2 0r 3 dimensional, so you need 3 points to define a plane.
<em>Angle-</em>
An angle measures the amount of turn. An angles is labeled with a single letter at the vertex, as long as it is perfectly clear that there is only one angle at this vertex. Otherwise, it is named according to the intersecting lines with 3 letters.
Profit (P) is calculated by subtracting the total cost (C) from the total revenue (R). The calculations are shown below,
R = (1440 dozens) x (12 pieces / 1 dozen) x (25 cents/ piece) = $4320
C = (1440 dozens) x ($2.50 / dozen) = $3600
Profit = R - C = $4320 - $3600 = $720
Thus, the businessman's profit is $720.
Answer:
B) b-7/b-7=b-1
Step-by-step explanation:
the same number as both the numerator and denominator is equal to 1
Sorry if this doesn't really help I am bad at explaining...
Option A
The system of equations are x + y = 40 and 10x + 7y = 360
<em><u>Solution:</u></em>
Let pounds of expensive coffee beans be x
Let pounds of cheaper coffee bean be y
Cost of 1 pound of expensive coffee bean = $ 10
Cost of 1 pound of cheaper coffee bean = $ 7
<em><u>The shop also sells a 40 pound mixture of the two kinds of coffee beans</u></em>
pounds of expensive coffee beans + pounds of cheaper coffee bean = 40
x + y = 40 ------ eqn 1
<em><u>The shop also sells a 40 pound mixture of the two kinds of coffee beans for $9 per pound</u></em>
pounds of expensive coffee beans x Cost of 1 pound of expensive coffee bean + pounds of cheaper coffee bean x Cost of 1 pound of cheaper coffee bean = 40 pound mixture x $ 9

10x + 7y = 360 --------- eqn 2
Thus the system of equations are x + y = 40 and 10x + 7y = 360
Thus option A is correct
Answer:
postive 6
Step-by-step explanation:cause negative plus a negative equals a postive