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Annette [7]
2 years ago
12

Help me please i need it

Mathematics
1 answer:
Sedbober [7]2 years ago
6 0

Answer:C

Step-by-step explanation:

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In ΔXYZ, x = 8.3 meters, y = 9 meters, and z = 15 meters. Find the remaining measurements of the triangle, and round your answer
laila [671]

Answer:

<u>The correct answer is B. ∠X = 28.6°, ∠Y = 31.2°, ∠Z = 120.2°</u>

Step-by-step explanation:

Let's recall that for solving a SSS triangle, we :

1. Use the Law of Cosines first to calculate one of the angles

2. Use The Law of Cosines again to find another angle

3. Finally use angles of a triangle add to 180° to find the last angle.

1. Cos x = (9² + 15² - 8.3²/2 * 9 * 15)

Cos x = (81 + 225 - 68.89/270)

Cos x = 0.878

x = Cos ⁻¹ (0.878)

x = 28.6° (rounding to the next tenth)

2. Cos y = (8.3² + 15² - 9²/2 * 8.3 * 15)

Cos y = (68.89 + 225 - 81/249)

Cos y = 0.855

x = Cos ⁻¹ (0.855)

x = 31.2° (rounding to the next tenth)

3. z = 180 - 31.2 - 28.6

z = 120.2°

<u>The correct answer is B. ∠X = 28.6°, ∠Y = 31.2°, ∠Z = 120.2°</u>

4 0
3 years ago
Solve the following equation. Then place the correct number in box provided.
Pepsi [2]

x is equal to 0 because 6 is already equal to 6

so there shouldnt be another number unless its 0

0+6=6

7 0
3 years ago
Can you help me please I need help :,)
Naddik [55]

Answer:

24v+8

Step-by-step explanation:

Calculations

8 0
2 years ago
Read 2 more answers
What is the area, in square meters, of a right triangle with sides of length 8 meters, 15 meters, and 17 meters?
cestrela7 [59]

I believe it would be E. YW

6 0
3 years ago
Question:
DanielleElmas [232]

Given A room is half as long again as it is broad

Let the breadth of the room x m

length of the room x + x/2 = 3x/2m

Area of the room , x × 3x/2 =<em> 3x²/2m</em>

Given , cost of carpeting the room at Rs. 3.25m⁻²

So , total cost , 3x²/2 × 3.25

But , Total cost of carpeting is given as 175.50 so ,

  • (3x²/2 )× 3.25 = 175.50
  • x² = 175.50 × 2 / 3.25 × 3
  • x² = 36
  • x = 6

  • Breadth x = 6 m
  • length 3x/2 = 9m

let the height of the room H m

Area of the four wall = 2(L+ b)× h 2(6+9)× H

= 30H m²

Area of the of the one door and two window is 8m²

8m² Area to be prepared = Area of four wall - area of two window and 1 door = (30H - 8) m²

Given cost of preparing wall is Rs. 1.40m²

total cost of preparing wall is (30H - 8) × 1.40

Total cost of preparing wall is given as 240.80

comparing , (30H - 8 ) × 1.40 = 240.80

  • (30H - 8 ) = 240.80 /1.40 = 172
  • 30H -. 8 = 172
  • 30H = 180
  • H = 180/30 = 6

Hence, Dimensions of the room are lengths 9m , breadth 6m and height 6m

3 0
2 years ago
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