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2 years ago

How do you expand 5(2x - 1)?

Mathematics

2 answers:

vlabodo [156]2 years ago

6 0

Hey there!

5(2x - 1)

DISTRIBUTE 5 WITHIN THE PARENTHESES

= 5(2x) + 5(-1)

= 10x - 5

Therefore, your answer is: 10x - 5

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

dybincka [34]2 years ago

4 0

Multiply 5 by each number in the parentheses

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The given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Step-by-step explanation:

Here, the given expression is: $(\frac{5}{6} a^{9}p^{5}) ^{3}$

Now, starting from the outer most bracket.

As we know :

$(abc)^{n} = (a)^{n} \times (b)^{n} \times (c)^{n}$

and $(a^m)^{n} = a^{(m \times n)}$

⇒ $(\frac{5}{6} a^{9}p^{5}) ^{3} = (\frac{5}{6})^{3} \times (a^{9})^{3} \times (p^{5}) ^{3}\\$

$=\frac{125}{216} \times (a)^{(9\times3) } \times (p)^{(5 \times 3)}\\= \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Hence, the given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

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So I’m only answering so I can ask you a question

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