Answer:
f(g(3)) = 3
Step-by-step explanation:
We are told to solve for f(g(3)). This is also saying f of g of 3.
To find f(g(3)), we need to plug 3 in for x in g(x), since it says g(3).
g(x) = 3(3) - 4
Solve.
= 9 - 4
g(x) = 5
Now, we plug that into f(x), because g(x) was placed inside f and replaces the x variable of f(x).
f(5) = 2(5) - 7
Solve.
= 10 - 7
f(5) = 3.
f(g(3)) = 3
#teamtrees #WAP (Water And Plant)
Answer:
7/5
Step-by-step explanation:
Answer:
PO = 20
Step-by-step explanation:
They are equidistant from the centre
PG = GO
x-4=1/2x+3
Multiplying both sides by 2
2(x-4)=x+6
2x-8=x+6
2x-x = 6+8
x = 14
Now
PO = 14-4+7+3
PO = 10+10
PO = 20
Answer:
Maximize C =
and x ≥ 0, y ≥ 0
Plot the lines on graph
So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)
Substitute the points in Maximize C
At (0,1.7)
Maximize C =
Maximize C =
At (2.125,0)
Maximize C =
Maximize C =
At (0,0)
Maximize C =
Maximize C =
So, Maximum value is attained at (2.125,0)
So, the optimal value of x is 2.125
The optimal value of y is 0
The maximum value of the objective function is 19.125
Step-by-step explanation:
cos θ = 3 / AB
When θ = 28°:
cos 28° = 3 / AB
AB = 3 / cos 28°
AB ≈ 3.4
When AB = 5.2:
cos θ = 3 / 5.2
θ = cos⁻¹(3 / 5.2)
θ ≈ 54.8°
