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dem82 [27]
2 years ago
10

Find the total surface area of the cube-shaped gift below

Mathematics
2 answers:
garri49 [273]2 years ago
6 0

Answer:

24

Step-by-step explanation:

:)

Anna35 [415]2 years ago
4 0

Answer:

24 ft²

Step-by-step explanation:

1. Start by finding the surface area of one of the faces

Since the length of the side is 2ft:

A=s²

A=2 ft²

A=4 ft²

2. Since there are 6 faces we multiply the area by 6.

S=4 ft²*6

S=24 ft²

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A

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Help please asap!!!!!!​
Free_Kalibri [48]

Answer: i would help but i have no idea but i think its (a)

Step-by-step explanation:

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7 0
3 years ago
90 x= 81 + 25 <br> I need help ?
charle [14.2K]

Answer:

x = \frac {53} {45}

Step-by-step explanation:

<u>Step 1:  Combine on the right side </u>

90x = 81 + 25

90x = 106

<u>Step 2:  Divide both sides by 90 </u>

\frac {90x} {90} = \frac {106} {90}

x = \frac {106/2} {90/2}

x = \frac {53} {45}

Answer:  x = \frac {53} {45}

4 0
3 years ago
Read 2 more answers
Construct a triangle with the given angle measures and classify the triangle: 15, 75, 90
mario62 [17]
The length of the triangle should be 60
5 0
3 years ago
Karma is building a rectangular table with an area of 18,000 cm?. He wants to put wood trim around the four edges. What is the s
jok3333 [9.3K]

The shortest length is given by the function for the perimeter of the

rectangular table.

  • The shortest length of trim he could use is <u>536.66 cm</u>
<h3>Method used for finding the shortest length of trim</h3>

The given parameter;

Area of the rectangular table Karma is building, <em>A</em> = <u>18,000 cm²</u>

Required:

The shortest length of trim he could use which he wants to put around the four edges.

Solution:

Let <em>l</em> represent the length of the table, and let <em>w</em> represent the width, therefore;

Perimeter of the table, <em>P</em> = 2·l + 2·w

Area, <em>A</em> = l × w

Which gives;

18,000 = l × w

l = \dfrac{18,000}{w}

Which gives;

P = 2 \cdot \dfrac{18,000}{w} + 2 \cdot w

At the minimum point, we have;

\dfrac{d}{dw} P = \dfrac{d}{dw} \left(2 \cdot \dfrac{18,000}{w} + 2 \cdot w\right)= \mathbf{\dfrac{2 \cdot w^2 - 36,000}{w^2} }= 0

Which gives;

2·w² - 36,000 = w² × 0 = 0

2·w² = 36,000

w^2 = \dfrac{36,000}{2} = 18,000

The width of the rectangular table, <em>w</em> = √(18,000)

Length \ of \ the \ table\ l = \dfrac{18,000}{\sqrt{18,000} } = \sqrt{18,000}

Therefore;

The perimeter of the table, P ≈ 2 × √(18,000) + 2 × √(18,000) ≈ 536.656

The length of trim required = The perimeter of the rectangular table, <em>P</em>

Therefore;

  • The shortest length of the trim he could use, given to the nearest hundredth is <u>536.66 cm</u>

Learn more about area and perimeter of a figure here:

brainly.com/question/9135929

4 0
2 years ago
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