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3 years ago

Which equation has no solution?

Mathematics

1 answer:

Alina [70]3 years ago

7 0

Answer:

<em>The equation which has no solution is 5 + 2(3 + 2x) = x + 3(x + 1) . </em>(see below for work)

Step-by-step explanation:

4(x + 3) + 2x = 6(x + 2)

4x + 12 + 2x = 6(x + 12)

4x + 2x = 6x

6x = 6x

x ∈ ℝ

5 + 2(3 + 2x) = x + 3(x + 1)

5 + 6 + 4x = x + 3(x + 3)

11 + 4x = x + 3x + 3

11 + 4x = 4x + 3

11 = 3

x ∈ ∅ (CORRECT ANSWER)

5(x + 3) + x = 4(x + 3) + 3

5x + 15 + x = 4x + 12 + 3

6x + 15 = 4x + 12 + 3

6x + 15 = 4x + 15

6x = 4x

6x - 4x = 0

2x = 0

x = 0

4 + 6(2 + x) = 2(3x + 8)

4 + 12 + 6x = 6x + 16

4 ÷ 12 = 16

16 = 16

x ∈ ℝ

Hope this helps! :)

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Can someone help me?

Gnesinka [82]

Answer:

y =4(x-3)^2+2 => y=4x^2-24x+38

y=2(x-3)^2+4 => y=2x^2-12x+22

y=2(x+3)^2+4 => y= 2x^2+12x+22

Y= 4(x+3)^2+2 => y= 4x^2+24x+38

Step-by-step explanation:

5 0

2 years ago

Sheila is biking at a constant speed. She travels 54 meters in 9 seconds.

dalvyx [7]

It would take her 15 seconds to reach 90 meters

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1 year ago

Please someone help me giving brainliest :)

worty [1.4K]

Answer 4

6 goes into 24 4 times and since both the top and bottom are negative the answer is positive

7 0

3 years ago

Read 2 more answers

Which summation formula represents the series below? 1 + 2 + 6 + 24

krek1111 [17]

Question:

Which summation formula represents the series below? 1 + 2 + 6 + 24

(a) $\sum_{n=2}^{5}(n-1) !$

(b) $\sum_{n=0}^{3} n !$

(d) $\sum_{n=2}^{5} n !$

Answer:

Option a: $\sum_{n=2}^{5}(n-1) !$ is the correct answer.

Explanation:

Option a: $\sum_{n=2}^{5}(n-1) !$

By substituting the values of n and expanding the summation, we have,

$(2-1) !+(3-1) !+(4-1) !+(5-1) !$

Subtracting, we have,

$1 !+2!+3 !+4 !$

Expanding the factorial,

$1+(2*1)+(3*2*1)+(4*3*2*1)$

Simplifying, we get,

$1+2+6+24$

Thus, the summation $\sum_{n=2}^{5}(n-1) !$ represents the series $1+2+6+24$

Hence, Option a is the correct answer.

Option b: $\sum_{n=0}^{3} n !$

By substituting the values of n and expanding the summation, we have,

$0!+1!+2!+3!$

Expanding the factorial,

$0+1+(2*1)+(3*2*1)$

Simplifying, we get,

$0+1+2+6$

Thus, the summation $\sum_{n=0}^{3} n !$ does not represents the series $1+2+6+24$

Hence, Option b is not the correct answer.

Option c: $\sum_{n=1}^{4}(n+1) !$

By substituting the values of n and expanding the summation, we have,

$(1+1) !+(2+1) !+(3+1) !+(4+1) !$

Adding, we have,

$2!+3!+4!+5!$

Expanding the factorial,

$(2*1)+(3*2*1)+(4*3*2*1)+(5*4*3*2*1)$

Simplifying, we get,

$2+6+24+120$

Thus, the summation $\sum_{n=1}^{4}(n+1) !$ does not represents the series $1+2+6+24$

Hence, Option c is not the correct answer.

Option d: $\sum_{n=2}^{5} n !$

By substituting the values of n and expanding the summation, we have,

$2!+3!+4!+5!$

Expanding the factorial,

$(2*1)+(3*2*1)+(4*3*2*1)+(5*4*3*2*1)$

Simplifying, we get,

$2+6+24+120$

Thus, the summation $\sum_{n=2}^{5} n !$ does not represents the series $1+2+6+24$

Hence, Option d is not the correct answer.

Hence, the correct answer is Option a: $\sum_{n=2}^{5}(n-1) !$

6 0

3 years ago

How would you rewrite -9/-6

attashe74 [19]

Answer:

3/2 or 1.5

Step-by-step explanation:

A negative divided by a negative makes the quotient a positive, 9 divided by 6 is 1.5 and the gcf of 9 and 6 is 3, so you would simplify it by doing 9 divided by 3 and 6 divided by3 which is 3/2

4 0

3 years ago