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Anon25 [30]
2 years ago
12

Parallelogram ABCD is shown.​

Mathematics
1 answer:
hichkok12 [17]2 years ago
3 0

Answer:

Step-by-step explanation:

#4 part A= D

#4 part B = 76

Your question only states parrallelogram ABCD is shown, so I assume you only wanted those answers, GL

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Show work how you know it’s a function or not a function for each problem. PLEASE SOMEONE HELP ME OUT
Fudgin [204]

Answer: Function, not a function, Function, not a function

Step-by-step explanation:

For it to be a function, each value of x has to map onto one value of y.

  1. This is a function.
  2. Not a function since x=-1 has more than one y value.
  3. This is a function
  4. Not a function since x=-6 has more than one y value.
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Y = (- 2x - 4)² + 1<br> what transformations were done?
Lina20 [59]

Answer:

No x-intercept/Zero

Step-by-step explanation:

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3(4 + Зр)<br> How do u solve this?
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12 + 9p distribute the 3
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How many halves go into 40
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We divide 40 by 1/2:-

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3 years ago
Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

 Hence, III is not true.

IV. y =x^{3}

Replacing y with and x with y:

x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
3 years ago
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