Wonderful! You gave us everything we could ever possibly want
to know, except the QUESTION. Fortunately, here at Brainly, we
have five Hogwarts drop-outs who work weekends for us as our
Department of Clairvoyance. When people post an intriguing
question but leave out some important part of it, our D of C can
usually fill in the missing part for us ... especially on weekends.
The question you left out is:
What is the next time that a red bus and a blue bus
will both leave the stadium together, simultaneously
and also both at the same time ?
Since red buses leave every 6 minutes starting at 4:00, and
blue buses leave every 8 minutes starting at 4:00, they both
leave simultaneously and also at the same time at minutes
after 4:00 that are common multiples of 6 and 8.
The least common multiple of 6 and 8 is 24 . After that,
every multiple of 24 is another common multiple of 6 and 8.
24 minutes is 4 red buses and 3 blue buses ... exactly !
A red bus and a blue bus will leave the stadium together at 4:24 .
After that, it will happen again at 24-minute intervals ... at 4:48,
5:12, 5:36, 6:00, . . . etc.
Cube= 1/6
coin= 1/2
1/2*3= 3/6
3/6+1/6= 4/6
4/6= 2/3
The answer is 4/6 or 2/3
Answer:
n = -6
Step-by-step explanation:
<u>Step 1: Divide both sides by 4</u>
4n / 4 = -24 / 4
n = -6
Answer: n = -6
Look at number 3 for the answer
Answer:
16 bicycles and 21 tricycles
Step-by-step explanation:
Both bicycles and tricycles have 1 set of handlebars. Bicycles have 2 wheels while tricycles have 3.
Using this information, set up a system of equations, where b is the number of bicycles and t is the number of tricycles:
b + t = 37
2b + 3t = 95
Solve by elimination by multiplying the top equation by -2:
-2b - 2t = -74
2b + 3t = 95
t = 21
Then, plug in 21 as t into one of the equations:
b + t = 37
b + 21 = 37
b = 16
So, there are 16 bicycles and 21 tricycles
