Let the width of room be =x mtrs
Then the length is x+2 mtrs
As Perimeter = 2(l+b) = 2(x+x+2)
16 = 2 ( 2x+2)
16/2 = 2x +2
8=2x+2
2x= 8-2 = 6
x = 6/2 =3 mtrs
Therefore width of the room is 3 mtrs
Let, the numbers = x,y
x+y= 24 1st eqn
x-y = 44 2nd eqn
24-y-y = 44
-2y = 44-24
y = 20/-2 = -10
substitute that in equation 1st x = 24+10 = 34
so, the numbers would be 34 & -10
