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zhannawk [14.2K]
3 years ago
14

Triangle PQR has coordinates P(–8, 3), Q(–8, 6), and R(–3, 6). If the triangle is translated by using the rule (x, y) right-arro

w (x + 4, y minus 6), what are the coordinates of triangle P prime Q prime R prime? (a)P prime (negative 12, 9), Q prime (negative 12, 12), R prime (negative 7, 12) (b)P prime (negative 4, 7), Q prime (negative 14, 0), R prime (1, 10) (c)P prime (negative 4, 9), Q prime (negative 4, 12), R prime (1, 12) (d)P prime (negative 4, negative 3), Q prime (negative 4, 0), R prime (1, 0)
Mathematics
1 answer:
omeli [17]3 years ago
6 0

Answer:

d

Step-by-step explanation:

The rule (x, y ) → (x + 4, y - 6 )

means add 4 to the original x- coordinate and subtract 6 from the original y- coordinate, thus

P(- 8, 3 ) → P'(- 8 + 4, 3 - 6 ) → P'(- 4, - 3 )

Q(- 8, 6 ) → Q'(- 8 + 4, 6 - 6 ) → Q'(- 4, 0 )

R(- 3, 6 ) → R'(- 3 + 4, 6 - 6 ) → R'(1, 0 )

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Karo-lina-s [1.5K]

Answer:

8/3

Step-by-step explanation:

7 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!
Furkat [3]
Here, (7 * 9) = (7 * 10) - (7 * x)

Here, Take 7 as a common factor according to distributive property:

= 7(10 - x)

Now, 10-x = 9
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3 0
3 years ago
Complete the table of inputs for the given function.
Alecsey [184]

Answer:

a. x = \frac{3}{8}

b. g(0) = 3

c. x = 1

d. g(3) = -21

Step-by-step explanation:

Given

g(x) = 3 - 8x

Solving (a): When g(x) = 0

Substitute 0 for g(x)

g(x) = 3 - 8x

0 = 3 - 8x

Solve for 8x

8x = 3

Solve for x

x = \frac{3}{8}

Solving (b): when x = 0

Substitute 0 for x

g(x) = 3 - 8x

g(0) = 3 - 8 * 0

g(0) = 3 - 0

g(0) = 3

Solving (c): When g(x) = -5

Substitute -5 for g(x)

g(x) = 3 - 8x

-5 = 3 - 8x

Solve for 8x

8x = 3 + 5

8x = 8

Solve for x

x = \frac{8}{8}

x = 1

Solving (d): When x = 3

Substitute 3 for x

g(x) = 3 - 8x

g(3) = 3 - 8 * 3

g(3) = 3 - 24

g(3) = -21

3 0
3 years ago
How do electromagnets differ from regular magnets?
Ira Lisetskai [31]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Factorize 2a^2+7a-15​
loris [4]

\huge\bf  \pink {\underline{Solution :-}}

2 {a}^{2}  + 7a - 15

= 2 {a}^{2}  + 10a - 3a - 15

= 2a(a + 5) - 3(a + 5)

= (a + 5)(2a - 3)

\sf \red{Hence, Answer \:  is  \: (a + 5)(2a - 3).}

\\

\bf \purple{ \underline{ Important  \: Formulas  \: for  \: Factorization :-}}

• \:  {a}^{2}  + 2ab + {b}^{2} =  {(a + b)}^{2}

• \: (a + b)(a - b) =  {a}^{2}  -  {b}^{2}

• \:  {a}^{2} - 2 ab  +  {b}^{2}  =  {(a - b)}^{2}

• \:  {a}^{3}  + 3 {a}^{2} b + 3a {b}^{2}  +  {b}^{3} =  {(a + b)}^{3}

• \:  {a}^{3}   -  3 {a}^{2} b + 3a {b}^{2}   -  {b}^{3} =  {(a  - b)}^{3}

•  \:  {(a + b)}^{2}  +  {(a - b)}^{2}  = 2( {a}^{2}  +  {b}^{2} )

• \: {(a + b)}^{2}   -   {(a - b)}^{2}  = 4ab

• \: (a + b)( {a}^{2}   -ab   +  {b}^{2}  ) =  {a}^{3}  +  {b}^{3}

• \: (a  -  b)( {a}^{2}    + ab   +  {b}^{2}  ) =  {a}^{3}   -  {b}^{3}

• \:   {( \frac{a + b}{2} )}^{2}  - ( {\frac{a - b}{2} } )^{2}  = ab

5 0
3 years ago
Read 2 more answers
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