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anyanavicka [17]
3 years ago
10

Just need correct answer.

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
6 0

Answer:

The answer is 61

Step-by-step explanation:

tino4ka555 [31]3 years ago
3 0

Its B I just did it on a test

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Write the equation of the line containing the points (3, 6) and (7, - 2) in standard form.
Rama09 [41]

Answer:

y = mx + c \\ 6 = 3m + c...(1) \\  - 2 = 7m + c...(2) \\ subtract \: (2) - (1) \\ 4m =  - 8 \\  \therefore \: m  = - 2 \: sub \: in \: (1) \\ 6 = 3( - 2) + c \\ \therefore \: c  = 12 \\  \boxed{y =  - 2x + 12}

7 0
2 years ago
Read 2 more answers
In ΔABC, if m∠CAD = 29°, the m∠DAB is......
daser333 [38]

Answer:125

Step-by-step explanation:

6 0
3 years ago
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
What's 7⁄8 as a decimal? A. 8.7 B. .875 C. .78 D. 7.8
LuckyWell [14K]
7/8 is equal to 0.875
3 0
3 years ago
Read 2 more answers
Which rules of exponents will be used to evaluate the expression. Check all that apply
julia-pushkina [17]

Hello!

The answer are:

- Product of powers.

- Power of a power.

- Negative exponents.

<h2>Why?</h2>

Let's solve it!

It's a math rule that we must solve first what's into a brake or parenthesis, so,

First: Product of powers [(7)^{5}*(7)^{3}]

According to the exponent's law, we have a product of powers case, so, we need to sum the exponents and keep the base

Exponents: 5 and 3

Base: 7

Applying it we have:

(7)^{5+3}

(7)^{8}

Then,

We have a power of a power case, which involves multiplying the exponents:

[(7)^{5}*(7)^{3}]^{-4}

Exponents: 3 and -4

Then,

(7)^{8*-4}

Finally, we can apply the negative exponents, the negative exponent's rules state that negative exponents are the reciprocal of the positive exponents,

So, we will have that:

(7)^{-32}=\frac{1}{7^{32} }

Have a nice day!

6 0
3 years ago
Read 2 more answers
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