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anyanavicka [17]

2 years ago

10

Just need correct answer.

2 answers:

Harlamova29_29 [7]2 years ago

6 0

Answer:

The answer is 61

Step-by-step explanation:

tino4ka555 [31]2 years ago

3 0

Its B I just did it on a test

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If Martin scored a 77 and an 83 on his last two quizzes, what was his quiz average

mihalych1998 [28]

His average is 80%. You take the two scores add them up and divide by the number of scores.

6 0

2 years ago

Stats 10: <br> J and K are independent events. P(J/K)=0.1. Find P(J)

Alik [6]

P(J/K) = 0.1 means that the probability of event J happening with respect to K is 0.1.However, since J and K are independent events, they are not related to each other. Thus, what ever the probability of event K is, it would not affect the probability of event J happening. So, P(J) would still be equal to 1.

7 0

2 years ago

Read 2 more answers

What is the approximate volume of a cone with a height of 8 cm and a radius of 12 cm? Use 3.14 for pie.

lawyer [7]

Answer:

A

Step-by-step explanation:

The volume of the cone is found using the volume formula for a cone $V=\frac{1}{3}\pi r^2h$ .

Substitute h=8 and r = 12.

$V = \frac{1}{3}\pi r^2h\\V = \frac{1}{3}\pi (12^2)(8)\\V=\frac{1}{3}\pi *144*8\\V = \frac{1152}{3}\pi \\V= 384\pi \\V=1,205.76$

So the volume is approximately 1,206 cubic cm.

3 0

3 years ago

45.15 divied by 21 equal but the estimate

pav-90 [236]

Answer:

The answer is 2.00.

Step-by-step explanation:

45.15 ÷ 21 = 2.15

2.15 rounded off to the nearest whole number is 2.00.

This was because you asked for an estimate.^

3 0

2 years ago

Does the set {t, t Int} form a fundamental set of solutions for t^2y" -- ty' +y = 0?

Ivanshal [37]

Answer:

yes

Step-by-step explanation:

We are given that a Cauchy Euler's equation

$t^2y''-ty'+y=0$ where t is not equal to zero

We are given that two solutions of given Cauchy Euler's equation are t,t ln t

We have to find the solutions are independent or dependent.

To find the solutions are independent or dependent we use wronskain

$w(x)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}$

If wrosnkian is not equal to zero then solutions are dependent and if wronskian is zero then the set of solution is independent.

Let $y_1=t,y_2=t ln t$

$y'_1=1,y'_2=lnt+1$

$w(x)=\begin{vmatrix}t&t lnt\\1&lnt+1\end{vmatrix}$

$w(x)=t(lnt+1)-tlnt=tlnt+t-tlnt=t$ where t is not equal to zero.

Hence,the wronskian is not equal to zero .Therefore, the set of solutions is independent.

Hence, the set {t , tln t} form a fundamental set of solutions for given equation.

6 0

3 years ago