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Rudiy27
3 years ago
13

(0,-9);slope=4

Mathematics
1 answer:
cestrela7 [59]3 years ago
8 0
1. y=4x-9
2. y=-3x+1
3. y=x-3
4. y=5x-11
5. y=5/6x-3
6. y=-2x+6

I’m not sure how to explain this but basically, if you have y=mx+b (the answer), the equation used to find that is y-y1=b(x-x1). b=slope

It’s kind of confusing but I’ll use the first question as an example.

So, y+9=4(x-0) You would substitute in your x, y, and slope and solve it from there. It’s a bit confusing at first but once you understand it’s easy.
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Multiply (3x+2) (4x+5)
maksim [4K]

Answer:

So all you need to do is Combine like terms which gives you a answer of

12x2 + 23x + 10 Hope this helps :)

Step-by-step explanation:


8 0
3 years ago
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A rectangle has a long side of length 8.5 cm its perimeter is 34 cm
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Answer
The other length is also 8.5

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wo balls are chosen randomly from an um containing 8 white, 4 black,and 2 orange balls. Suppose that we win $2 for each black ba
umka21 [38]

Answer:

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (<em>W</em>), 4 black (<em>B</em>) and 2 orange (<em>O</em>) balls.

The winning and losing criteria are:

  • Win $2 for each black ball selected.
  • Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, {14\choose 2}=91 ways.

The distribution of amount won or lost is as follows:

Outcomes: WW  WO  WB  BB  BO  OO

X:                 -2      -1      1      4     2      0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, {8\choose 2}=28 ways.

The probability of WW is,

P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, {8\choose 1}\times {2\choose 1}=16 ways.

The probability of WO is,

P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, {8\choose 1}\times {4\choose 1}=32 ways.

The probability of WB is,

P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, {4\choose 2}=6 ways.

The probability of BB is,

P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, {4\choose 1}\times {2\choose 1}=8 ways.

The probability of BO is,

P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, {2\choose 2}=1 ways.

The probability of OO is,

P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110

The probability distribution of <em>X</em> is:

Outcomes:    WW     WO        WB         BB        BO         OO

X:                    -2          -1            1            4            2            0

P (X):           0.3077  0.1758  0.3516  0.0659  0.0879  0.0110

3 0
3 years ago
maria bought 20 apples and oranges for her kids school lunches apples cost 40 cents each and oranges cost 35 cents each she spen
dedylja [7]
15 x 0.4 = 6 ($6)

5 x 0.35 = 1.75 ($1.75)

15 + 5 = 20 (20 Fruit)

6 + 1.75 = 7.75 ($7.75)

Answer: 15 Apples and 5 Oranges will get you 20 Fruits for $7.75.

Hope this helps!

-Iceland
4 0
3 years ago
Joey has read 140 pages of his 300 page book.What % of the book has he read?
Irina-Kira [14]
<span>46.6666666667 this is the actual answer but if rounded to the nearest tens, its 50.</span>
3 0
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