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velikii [3]
3 years ago
7

Shayna pays 20 for 5 bottles of juice. What is the unit price for the bottles of juice?

Mathematics
1 answer:
Goshia [24]3 years ago
3 0
20/5 = 4
therefore the unit price for the bottles of juice is 4
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Jemima bought 150 oranges at ¢12 and sold them at 6 for 30gp find the profit or loss​
stepan [7]

Answer:

<h2>The loss is ¢ 4.50</h2>

Step-by-step explanation:

To calculate either the profit or loss we must first find the cost price and the selling price

<u>For the cost price</u>

She bought 150 oranges at ¢12

Cost price = ¢ 12.00

<u>For the selling price</u>

She sold 6 at 30 Gp that's ¢ 0.30

If she sold 6 at ¢ 0.30

Then 150 will be 150× 0.3/ 6

Selling price = ¢ 7.50

Since the cost price is higher than the selling price she made a loss

Loss = Cost price - Selling price

Loss = ¢ 12 - ¢ 7.50

<h3>Loss = ¢ 4.50</h3>

Hope this helps you

8 0
3 years ago
Work the following pricing problems for services rendered. (Round to the hundredths.)
prisoha [69]
Hi there

Total cost of job=
Retail price of goods+labor cost+OH

First find the labor cost
Labor cost=worker A+worker B+worker C
Worker A=13×1.5=19.5
Worker b=9.5×(1+3÷4)=16.63
Worker C=5×(2+3÷4)=13.75
Total labor cost
=19.5+16.63+13.75=49.88

Overhead cost49.88×0.75=37.41

Total cost of job is
74.5+49.88+37.41=161.79

So it's option d

Hope it helps



8 0
3 years ago
Read 2 more answers
write the product of the expression 5^4 * 5^-7 using a positive exponent, then write the product using a negative exponent
pav-90 [236]

Answer with positive exponent = \left(\frac{1}{5}\right)^3 or  \frac{1}{5^3}

Answer with negative exponent = 5^{-3}

===========================================================

Explanation:

The rule we use is

a^b*a^c = a^{b+c}

If we multiply two exponential expressions with the same base, then we add the exponents.

The base for each is 5. The exponents 4 and -7 add to -3.

This means

5^4*5^{-7} = 5^{4+(-7)} = 5^{-3}

To convert to a positive exponent, we apply the reciprocal to the base. We go from 5, aka 5/1, to 1/5.

So, 5^{-3} = \left(\frac{1}{5}\right)^3 = \frac{1^3}{5^3} = \frac{1}{5^3}

3 0
3 years ago
How can I find the complex roots of 125x^3+343. Please explain your steps
8_murik_8 [283]
First we assume that this is equal to zero

so what we notice is this is a sum of 2 perfect cube

recall that
a^3+b^3=(a+b)(a^2-ab+b^2)

125x^3+343=
(5x)³+(7)³=(5x+7)(25x²-35x+49)

now solve the part in second parenthasees because we can see that the first parenthasees (5x+7) is going to have a real root

remember quadratic formula

for ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
a=25
b=-35
c=49

x=\frac{-(-35)+/- \sqrt{(-35)^2-4(25)(49)} }{2(25)}
x=\frac{35+/- \sqrt{1225-4900} }{50}
x=\frac{35+/- \sqrt{-3675} }{50}
x=\frac{35+/- (\sqrt{3675})( \sqrt{-1}) }{50}
x=\frac{35+/- (\sqrt{3675})(i) }{50}
x=\frac{35+/- 35i\sqrt{3} }{50}
x=\frac{7+/- 7i\sqrt{3} }{10}

the comlex roots are

x=\frac{7+ 7i\sqrt{3} }{10} and \frac{7- 7i\sqrt{3} }{10}




3 0
4 years ago
In ΔEFG, EG is extended through point G to point H,angle FGH = (4x-1) m∠FGH=(4x−1) ∘ , angle GEF = (x+18) m∠GEF=(x+18) ∘ , and a
Illusion [34]

Answer:

x=346

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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