Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Answer:
-1 < x < 4.
Step-by-step explanation:
- 6 < 2x - 4 <4
2x - 4 < 4
2x < 8
x < 4. Also we have:
2x - 4 > -6
2x > -2
x > -1.
I can't see the photo!????????
Answer:
he makes 14 field goals and 7 extra point kicks
Step-by-step explanation:
- f=#of field goals
- e=extra kick points
- f+e=21
- 3f+1e=49
- subtract top from bottom
- 2f=28
- f=14
6a+12=2(3a-8)
6a+12=6a-16
-12. -12
6a=6a-4
-6a -6a
0=-4
no solution because the equation is false.
