<span>THE AREA OF THE ROOM IS :A=4*2.4=9.6 m^2
THICKNESS t=0.30 m
DIFFERENCE IN TEMPERATURE dT=18-6=12
q=kAdT/dx=kA*dT/t
q=1.3(9.6)(12)/0.30=4992 W=499.2 J/s
In 1 hour or 3600 sec
P=q*T=(499.2 J/s)(3600 s)=1797120 J=1.8 MJ
1.8MJ OF HEAT FLOWS HTROUGH THE WALL IN ONE HOUR</span>
two pairs of parallel sides are equal
The answer should be (x-4)^2+(y+2)^2=radical 26
Answer:
Step-by-step explanation:
Given that,
The base of the parallelogram, b = 2.5 cm
Height of the parallelogram, h = 1.25 cm
We need to find the area of the logo. The formula for the area of the parallelogram is given by :
So, the area of the logo is 
.
Answer:
x^2 -4x+13
Step-by-step explanation:
f(x)=x^2+9
Replace x with x-2
f(x-2)=(x-2)^2+9
FOIL
f(x-2)=x^2 -2x-2x +4+9
Combine like terms
= x^2 -4x+13
