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VashaNatasha [74]
2 years ago
8

Type a digit that makes this statement true. 691,61 is divisible by 4.

Mathematics
1 answer:
ASHA 777 [7]2 years ago
8 0
Okay so I am not sure but I think the answer is 172.9025
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The answer is 24/35.

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What graph is defined by the function given below? <br><br>y = (x-1)(x+4)
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The x intercepts must be 1 and -4, so C.
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3 years ago
WILL MARK BRAINLIEST!! PLZ HELP!!! 20 POINTS Create a graph of the polynomial function g(x) = (x + 2)(x − 1)(x − 2)
Gennadij [26K]

Answer:

We have: g(x)=(x+2)(x-1)(x-2)

multiply the 3 terms:

  • (x+2)(x-1)(x-2)
  • (x²-4)(x-1)
  • x^3 -x²-4x+4

This is a polynimial function with 2 vertices

The roots are approximatively:

0.8 and -1.5

their images are:

1.9 and 8.8

plot these two vertices and draw some other points

here is a drawing:

6 0
3 years ago
If the freshman class of 63 students has 11 more boys than girls, determine how many of each are in the class.g 1
torisob [31]
B + G = 63
B = G + 11

G + 11 + G = 63
2G + 11 = 63
2G = 63 - 11
2G = 52
G = 52/2
G = 26 <=== 26 girls

B = G + 11
B = 26 + 11
B = 37 <=== 37 boys

4 0
3 years ago
Find r'(t), r(t0), and r'(t0) for the given value of (t0). r(t) = (e^t, e²t), t0 = 0​
creativ13 [48]

Applying the differentiation rule, it can be obtained that:

r'(t)=(e^t,2e^{2t}), r(t_0)=(1,1) and r'(t_0)=(1,2).

<h3>What is the formula for differentiating an exponential function?</h3>

The exponential function exists a mathematical function designated by f(x)=\exp or e^{x}. Unless otherwise determined, the term generally directs to the positive-valued function of a real variable, although it can be extended to complex numerals or generalized to other mathematical objects like matrices or Lie algebras.

In mathematics, the derivative of a function of a real variable estimates the sensitivity to change of the function value affecting a change in its statement. Derivatives exist as a fundamental tool of calculus.

\frac{d}{dt}(e^{mt})=me^{mt}.

Given that r(t)=(e^t,e^{2t}).

So, differentiating r(t)=(e^t,e^{2t}) with respect to t, we get: r'(t)=\left(\frac{d}{dt}(e^t),\frac{d}{dt}(e^{2t})\right).

So, using the above formula \frac{d}{dt}(e^{mt})=me^{mt}, we get: r'(t)=(e^t,2e^{2t}).

Now, substituting t=t_0=0 in r(t)=(e^t,e^{2t}) and r'(t)=(e^t,2e^{2t}), we obtain:

r(t_0=0)=(e^0,e^{2\times 0})=(1,1) and r'(t_0=0)=(e^0,2e^{2\times 0})=(1,2).

Therefore, applying the differentiation rule, we get:

r'(t)=(e^t,2e^{2t}), r(t_0)=(1,1) and r'(t_0)=(1,2).

To know about the differentiation rule, refer:

brainly.com/question/25081524

#SPJ9

5 0
11 months ago
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