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3 years ago

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Is this a complementary ,linear pair,vertical or adjacent?

1 answer:

vovangra [49]3 years ago

6 0

Answer: Linear

Explanation: A linear pair of angles is formed when two lines intersect. Two angles are said to be linear if they are adjacent angles formed by two intersecting lines. The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

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Pls help me with thid

True [87]

The angle 1 and the side equal to 72° together equal 180. 72 + x = 180 using the subtraction property of equality we can conclude that x = 108.

Side 2 is parallel with 72° making them equal and Side 3 is parallel with 108° making them equal.

Side 1 = 108°
Side 2 = 72°
Side 3 = 108°

4 0

2 years ago

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X+9=3<br><br>please help ASAP

klasskru [66]

Step-by-step explanation:

$x + 9 = 3 \\ \\ x = 9 - 3 \\ \\ x = 6$

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2 years ago

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I have 2 Questions.

aleksandr82 [10.1K]

Answer:

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2 years ago

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Use the distributive property to find the product

dalvyx [7]

Answer:

1st one: -24a-6b-36c

2nd one: 14mn-12m

Step-by-step explanation:

1st one: Multiply '-6' w/ '4a', 'b', and '6c'

2nd one: Multiply '2m' w/ '7n' and '-6'

6 0

2 years ago

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What is the equation of the line that is perpendicular to y, =, 1 over 3 x, 4. And contains the point negative 2, negative 5,?.

Anit [1.1K]

The equation of the line is, $\rm y = 3x + 1$ .

Given that,

The equation of the line is,

$\rm y = \dfrac{1}{3} x+4\\$

And contains the point (-2, -5).

We have to determine,

What is the equation of the line that is perpendicular to the given line?

According to the question,

The equation of the line is,

$\rm = \dfrac{1}{3}x + 4\\$

On comparing with the standard equation of the line y = mx +c.

The slope of the line $m_1$ is 1/3.

When two lines are perpendicular the relation between these slopes is,

$\rm m_1\times m_1 = {-1}\\\\\dfrac{-1}{3} \times m_2 = -1\\\\-1 \times m_2 = -1 \times 3\\\\-m_2 = -3\\\\m_2 = 3$

And line contains the point (-2, -5).

Then,

$\rm y = mx +c \\\\-5 = 3 (-2) + c\\\\-5 = -6+c \\\\c = 6-5 \\\\c = 1$

Therefore,

The equation of the line that is perpendicular to the given line and contains the point (-2, -5) is,

$\rm y = mx +c \\\\y = 3x +1$

Hence, The required equation of the line is, $\rm y = 3x + 1$ .

For more details refer to the link given below.

brainly.com/question/14388443

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2 years ago