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mash [69]
2 years ago
15

Need help with this question.

Mathematics
1 answer:
Vaselesa [24]2 years ago
4 0

Answer:

4:1 (I think)

Step-by-step explanation:

Let's write some equations first:

For both prices increasing by 20:

\frac{x+20}{y+20} =\frac{5}{2}

then we can use cross multiplication

2x+40=5y+100

For both prices decreasing by 5:

\frac{x-5}{y-5} =\frac{5}{1}

same here:

5y-25=x-5

Using substitution for 5y, we get: 5y=x+20

2x+40=5y+100

2x+40=x+20+100

x=80

plugging this in to the second equation:

5y-25=x-5

5y-25=80-5

5y-25=75

5y=100

y=20

therefore we get x:y=80:20

4:1

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Answer:

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Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

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The two graphs intersect when:

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To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Let's recall that:

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