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4 years ago

How many unique triangles can be made where one angle measures 60 degrees and another is an obtuse angle

Mathematics

1 answer:

Svet_ta [14]4 years ago

4 0

An acute angle can also be made inside of that type of triangle.

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5) Establish the indentity (cot + tan ) sin = sec . Show each step to justify your conclusion.

katen-ka-za [31]

Answer:

Step-by-step explanation:

Identities : -

cot = cos / sin

tan = sin / cos

( cot + tan ) sin = sec

LHS

= ( cot + tan ) sin

= ( ( cos / sin ) + ( sin / cos ) ) sin

= ( ( cos sin ) / sin ) + ( sin² / cos )

= cos + ( sin² / cos )

LCM = cos

= ( cos² / cos ) + ( sin² / cos )

= ( cos² + sin² ) / cos

Identity : -

cos² + sin² = 1

= 1 / cos

= sec

= RHS

Hence proved.

3 0

3 years ago

Number one solve sin l and tan n cos l and sin n

const2013 [10]

Sin L= 3/5

Tan N= 3/5

Cos L=4/5

Sin N=4/5

5 0

3 years ago

HELP I HAVE ONLY 1 MIN TO ANSWER IT HELP(((((((&&&&

LenKa [72]

Answer:

the one you have marker is correct

Step-by-step explanation:

5 0

3 years ago

4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto rep

bagirrra123 [75]

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.92}{2} = 0.04$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.04 = 0.96$ , so Z = 1.88.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that $\sigma = 2.2$

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1 = 1.88\frac{2.2}{\sqrt{n}}$

$\sqrt{n} = 1.88*2.2$

$(\sqrt{n})^2 = (1.88*2.2)^2$

$n = 17.1$

Rounding up:

A sample of 18 is required.

3 0

3 years ago

I got a photo of the problem dude I need help I'm in an exam and I am cluelessssss

Doss [256]

Answer:

0.84

Step-by-step explanation:

1 - 0.4(0.4) = 1 - 0.16 = 0.84

Simply take the probability of the the outcome that is not " at least 1 win", which is the probability of 2 losses;

To find the probability multiply the probabilities along the branches.

6 0

3 years ago

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