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Nana76 [90]
3 years ago
5

Suppose CAequalsISubscript n ​(the ntimesn identity​ matrix). Show that the equation ABold xequalsBold 0 has only the trivial so

lution. Explain why A cannot have more columns than rows
Mathematics
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

See Explanation

Step-by-step explanation:

(a)For matrices A and C, given that: CA=I_n.

We want to show that Ax=0 has only the trivial solution

If Ax=0

Multiply both sides by C

C(Ax)=C \times 0\\\implies (CA)x=0$ (Recall: CA=I_n)\\\implies I_nx=0 $ (Since I_n$ is the n\times n$ identity matrix)\\\implies x=0

This means that the system has only the trivial solution.

(b)If the system has more columns than rows, a free variable would occur when a column does not have a pivot. This would lead to a non-trivial solution.

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3 years ago
Read 2 more answers
Help is needed please!
Schach [20]

The distance travelled is 10 m

The velocity gained at the end of the time is 2 m/s

<h3>Motion</h3>

From the question, we are to determine distance travelled and the velocity gained

From one of the equations of motion for <u>linear motion</u>, we have that

S = ut + 1/2at²

Where S is the distance

u is the initial velocity

t is the time taken

and a is the acceleration

First, we will calculate the acceleration

Using the formula,

F = ma

Where F is the force

m is the mass

and a is the acceleration

∴ a = F/m

Where F is the force

and a is the acceleration

From the given information,

F = 50 N

m = 250 kg

Putting the parameters into the equation,

a =  50/250

a = 0.2 m/s²

Thus,

From the information,

u = 0 m/s (Since the object was initially at rest)

t = 10 s

S = 0(t) + 1/2(0.2)(10)²

S = 10 m

Hence, the distance travelled is 10 m

For the velocity

Using the formula,

v = u + at

Where v is the velocity

v = 0 + 0.2×10

v = 2 m/s

Hence, the velocity gained at the end of the time is 2 m/s

Learn more on Motion here: brainly.com/question/10962624

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viva [34]

Step-by-step explanation:

Given g'(x) = g^{-2}, x> 0\ g(1) = 0 \ and \ g(2) = 0

To get g(x), we will have to integrate g'(x)

g(x)  = \int\limits {x^{-2}} \, dx\\ g(x)  = \frac{x^{-2+1}}{-2+1} + C\\ g(x) = -x^{-1} + C\\g(x) = -x^{-1} + C\\

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Substitute C = 1 into the function

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Substitute C = 2 into the function

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