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jeka57 [31]
3 years ago
6

Billy has 95 stickers. He shares 4 with Harry. How many stickers will Billy have?

Mathematics
2 answers:
Fantom [35]3 years ago
8 0

Answer:

you simply subtract the 4 stickers Billy gave out from the 95 stickers Billy had.

95-4

to get that Billy was left with 91 stickers

Leni [432]3 years ago
7 0

Answer: 91

Step-by-step explanation:

95 - 4 (That he gave to Harry) = 91

Hope this helped!

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a bucket contains 50 lottery balls numbered 1-50.one is drawn at random.Find p(multiple of 6/2-digit number)
Darina [25.2K]
This is a problem of conditional probability that can be calculated by the formula:
P(B | A) = P(A ∩ B) / P(A)

We know that:
- between 1 and 50 there are 41 two-digit numbers, therefore 
P(A) = 41/50 = 0.82

- between 1 and 50 there are 8 multiples of six, therefore
P(B) = 8/50 = 0.16

- <span>between 1 and 50 there are 7 two-digits mutiples of six, therefore
P(A ∩ B) = 7/50 = 0.14

Now, we can calculate:
</span>P(B | A) = P(A <span>∩ B) / P(A)
             = 0.14 / 0.82
             = 0.17

Therefore, the probability of getting a multiple of 6 if we draw a two-digit number is 17%.</span>
3 0
3 years ago
I need this answered plz!!!!!!!!!!!!!!!!!!!
Fynjy0 [20]

Answer:

Red: Left side equation

Blue: Right side equation

2x+7=2(x-1)

2x+7=2x-2

2x-2x=-2-7

0x=-9= 0 No solution

Step-by-step explanation:

Use Desmos graphing calculator if u need help with graphs

6 0
3 years ago
What is 28 percent of 486
Dimas [21]
136.08 hope this  helps
5 0
3 years ago
Read 2 more answers
Allie is 26 years old. This is half of her
SVETLANKA909090 [29]

Answer:

18

Step-by-step explanation:

8 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

7 0
3 years ago
Read 2 more answers
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