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kirill [66]
4 years ago
5

There are 45 students signed up for a performance band while 30 are signed up for a jazz band. If 19 students are signed up for

both bands, then how many students are signed up for only one of the two bands?
I tend to overthink constantly and I ended up with two answers: 56 students and 37 students. I am pretty sure it is 56 but I really need help to double check. Plz help me ​
Mathematics
1 answer:
Stels [109]4 years ago
8 0

45 students for performance

30 students for jazz

19 for both

Add the two bands first

45 + 30 = 75 students

Since there are 19 for both and the question is how many students signed up for only one of the two bands (not both bands).

75 - 19 = 56 students signed for one of the two bands

So you're good to go

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Solve for xxx in the diagram below.
hodyreva [135]

Answer: 15

Step-by-step explanation:30/2= 15

4 0
4 years ago
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Solve the limit given on the picture
lesya [120]
Pull out the highest power of n from each radical expression, then divide through the numerator and denominator by the largest power of n overall.

The largest power in the cube root is n^2; the largest power in the fourth root is n^{12}:

\displaystyle\lim_{n\to\infty}\frac{(n^2-1)^{1/3}+7n^3}{(n^{12}+n+1)^{1/4}-n}=\lim_{n\to\infty}\frac{n^{2/3}\left(1-\dfrac1{n^2}\right)^{1/3}+7n^3}{n^3\left(1+\dfrac1{n^{11}}+\dfrac1{n^{12}}\right)^{1/4}-n}

Now the largest power in the numerator and denominator is n^3, so we get

=\displaystyle\lim_{n\to\infty}\frac{\dfrac1{n^{7/3}}\left(1-\dfrac1{n^2}\right)^{1/3}+7}{\left(1+\dfrac1{n^{11}}+\dfrac1{n^{12}}\right)^{1/4}+\dfrac1{n^2}}

Every term containing n approaches 0 as n\to\infty, which leaves us with

=\displaystyle\lim_{n\to\infty}\frac{0(1-0)^{1/3}+7}{(1+0+0)^{1/4}+0}=\frac71=7
6 0
4 years ago
george has to pay $30 in taxes for every $100 that he earns.Last summer he earned $3,680.How much did he pay in taxes.
Ludmilka [50]
We can solve this problem by rule of 3:

$30 (taxes)------------$100
x-----------------------$3,680

x=($30*$3,680) / $100=$1,104


Answer: $1,104 paid  in taxes.
7 0
4 years ago
Tim is investigating the relationship between the number of years since a tree was planted and the height of the tree in feet. H
wolverine [178]

Answer: There is not a good prediction for the height of the tree when it is 100 years old because the prediction given by the trend line produced by the regression calculator probably is not valid that far in the future.

Step-by-step explanation:

Years since tree was planted (x) - - - - height (y)

2 - - - - 17

3 - - - - 25

5 - - - 42

6 - - - - 47

7 - - - 54

9 - - - 69

Using a regression calculator :

The height of tree can be modeled by the equation : ŷ = 7.36X + 3.08

With y being the predicted variable; 7.36 being the slope and 3.08 as the intercept.

X is the independent variable which is used in calculating the value of y.

Predicted height when years since tree was planted(x) = 100

ŷ = 7.36X + 3.08

ŷ = 7.36(100) + 3.08

y = 736 + 3.08

y = 739.08

Forward prediction of 100 years produced by the trendline would probably give an invalid value because the trendline only models a range of 9 years prediction. However, a linear regression equation isn't the best for making prediction that far in into the future.

3 0
4 years ago
Can someone please answer number 14 a, b and c? Thank you.
Harrizon [31]
For a, we have 42in/9ft. Since 12 inches are in 1 foot, we can multiply it by that to get (42in/9ft)*(1ft/12inches) = 42/108. We put the foot on the top of 1ft/12in to cancel them out. Since 2 goes into both 42 and 108, we divide it by 2/2 to get 26/54. Repeating the process again, we get 13/27

If we were to say that there are 12 inches in a foot and therefore divide 42 by 12 (to get 42 inches in feet), we'd get the same answer due to that 1 foot is equal to 12 inches and if you were to divide it by 1 foot/12 inches, since they are the same thing, you get the same answer

For c, since it may be hard to get (42/12)/9, it could just be easier to have 42/(9*12)=42/108
5 0
4 years ago
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