<u>Given</u>:
The measure of ∠EGF is 51°
We need to determine the measure of ∠EHF
<u>Measure of ∠EHF:</u>
By inscribed angle theorem, we know that, "if two inscribed angles of a circle intercept the same arc then the angles are congruent".
Applying the theorem, we have that the two inscribed angles of a circle intercepting the same arc are ∠G and ∠H
Then, the two angles are congruent.
Thus, we have;
∠G ≅ ∠H
Therefore, the measure of ∠G = ∠H = 51°
Hence, the measure of ∠EHF = 51°
Answer:
A. 3.5
Step-by-step explanation:
Given that AB is parallel to A'B', therefore,
CB/CB' = CA/CA'
CB' = 7
CB = CB' + BB' = 7 + BB'
CA' = 6
CA = CA' + AA' = 6 + 3 = 9
Plug in the values
(7 + BB')/7 = 9/6
(7 + BB')/7 = 3/2
Cross multiply
2(7 + BB') = 7(3)
14 + 2BB' = 21
Subtract 14 from both sides
2BB' = 21 - 14
2BB' = 7
Divide both sides by 2
BB' = 7/2
BB' = 3.5
Answer: 8.373205741626794e-4
Step-by-step explanation: Thant is what i got on my calculator
Answer:
2.8
Step-by-step explanation:
since 4/5 equals .8 it would just be 0.8 + 2
